小编mis*_*nne的帖子

调用printf()时,*b的值是否未定义？

void foo(int *a) {
  const int *b = a;
  int *c = a;
  *c = 2;
  printf("%d\n", *b); // what must be *b? 1, 2 or undefined?
}

int d = 1;
foo(&d);