我通过以下方式从数据库获取数据:
result = (from d in context.FTDocuments
join f in context.FTDocFlags on d.ID equals f.DocID into fgrp
from x in fgrp.DefaultIfEmpty()
where d.LevelID == levelID && x.UserID == userID && d.Status.Equals(DocumentStatus.NEW)
select new Entities.Document
{
ArrivalDate = d.ArrivalDate.Value,
BundleReference = d.BundleRef,
CreatedDate = d.CreatedDate,
CustomerID = d.CustomerID,
DocType = d.DocType.Value,
GuidID = d.DocGuid,
ID = d.ID,
LastExportID = d.LastExpID,
LevelID = d.LevelID,
ProfileID = d.ProfileID,
ScanDate = d.ScanDate.Value,
ScanOperator = d.ScanOperator,
SenderEmail = d.SenderEmail,
Status = d.Status,
VerifyOperator = d.VerOperator, …Run Code Online (Sandbox Code Playgroud) 以下输出为20121212.
DateTime dd = new DateTime(2012, 12, 12);
string val = String.Format("{0:yyyyMMdd}", dd);
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当格式在变量中时.以下不给出上述输出.
DateTime dd = new DateTime(2012, 12, 12);
string dateFormat = "yyyyMMdd";
string val = String.Format("{0}:{1}", dd, dateFormat);
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如何在上面的变量中使用格式来实现它?
在以下示例中,哪一个是最佳用途.如您所见,我只使用列表集合而没有命名空间中的任何其他内容.是这样的,当执行Example1时,命名空间system.collections.generic下的所有类都被加载到内存中或者是什么?这两个例子的表现如何?
Example1:
using System.Collections.Generic;
public interface ICustomer
{
List<Customer> GetAll();
}
Example2:
public interface ICustomer
{
System.Collections.Generic.List<Customer> GetAll();
}
Run Code Online (Sandbox Code Playgroud) 我是QlikView的新手.
我已经创建了一个测试QlikView应用程序.我想知道,是否可以在网络浏览器中访问该应用程序?如果有,怎么样?
让我直截了当.如果XMLArray元素为null,是否可以不序列化它?如下面的XML"详细信息"一样.如果它为null,是否可以不用XML.请检查我的代码,并会对它有一些想法.
<agr:InvoiceNo>99999</agr:InvoiceNo>
<agr:Header>
<agr:LineNo>1</agr:LineNo>
<agrlib:InvoiceDate>2013-02-13</agrlib:InvoiceDate>
<agrlib:DueDate>2013-03-15</agrlib:DueDate>
<agr:ArchiveRef>27624642</agr:ArchiveRef>
<agr:ArchivePath>Images\20130315\10_00000030_00000</agr:ArchivePath>
<agr:Currency>SEK</agr:Currency>
<agr:Seller>
<agrlib:CompRegNo>999999</agrlib:CompRegNo>
</agr:Seller>
<agr:Buyer>
<agrlib:CompanyCode>10</agrlib:CompanyCode>
<agr:Accountable />
</agr:Buyer>
<agr:PaymentInfo>
<agr:AccountNumber>99999</agr:AccountNumber>
<agrlib:BacsId />
</agr:PaymentInfo>
<agrlib:ReferenceCode>
<agrlib:Code>AA</agrlib:Code>
<agrlib:Value>AAAA</agrlib:Value>
<agrlib:Description />
</agrlib:ReferenceCode>
</agr:Header>
<Details /> <!-- this one -->
<agr:Summary>
<agr:TotalTax>170.36</agr:TotalTax>
<agr:TotalInclTax>1590.00</agr:TotalInclTax>
</agr:Summary>
</agr:Invoice>
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[Serializable]
public class Invoice
{
private Header _header = new Header();
private Summary _summary = new Summary();
private List<Detail> _details = new List<Detail>();
[XmlElement("InvoiceNo")]
public string InvoiceNo { get; set; }
[XmlElement("Header")]
public Header Header
{
get { return _header; …Run Code Online (Sandbox Code Playgroud) 我有 Oracle 数据库和 ASP.NET 设计的应用程序。我想在用户访问应用程序之前检查用户身份验证。用户是在 Oracle 中创建的,而不是在应用程序的表中创建的。
是否可以使用asp.net对Oracle数据库用户进行身份验证?
该应用程序使用 WebForms 和 Oracle .NET Data Provider 库。
编辑
(我可以成功连接Oracle,但无法验证Oracle用户)
请查看以下XML名称空间和schemaLocation。
<agr:ABWInvoice
xsi:schemaLocation = "
http://services.agresso.com/schema/ABWInvoice/2011/11/14
http://services.agresso.com/schema/ABWInvoice/2011/11/14/ABWInvoice.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:agrlib = "http://services.agresso.com/schema/ABWSchemaLib/2011/11/14"
xmlns:agr = "http://services.agresso.com/schema/ABWInvoice/2011/11/14"
>
</agr:ABWInvoice>
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我以以下方式添加了名称空间,这似乎工作正常:
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("xsi", "http://www.w3.org/2001/XMLSchema-instance");
ns.Add("agrlib", "http://services.agresso.com/schema/ABWSchemaLib/2011/11/14");
ns.Add("agr", "http://services.agresso.com/schema/ABWInvoice/2011/11/14");
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但是,如何添加以下schemalocation?有任何想法吗?
xsi:schemaLocation="http://services.agresso.com/schema/ABWInvoice/2011/11/14 http://services.agresso.com/schema/ABWInvoice/2011/11/14/ABWInvoice.xsd"
Run Code Online (Sandbox Code Playgroud) Invoice invoice = new Invoice();
invoice.TotalInclTax = 4194.00f;
invoice.serialize();
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我需要一些帮助来序列化浮点值。目前它对 4194.00 的序列化如下:
<TotalInclTax>4194</TotalInclTax>
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但是,我想要这样的东西:
<TotalInclTax>4194.00<TotalInclTax>
Run Code Online (Sandbox Code Playgroud) 我有UTF-8文件(瑞典语charactersåö字符).我读到这些:
List<MyData> myDataList = new List<MyData>();
string[] allLines = File.ReadAllLines(csvFile[0], Encoding.Default);
foreach (string line in allLines)
{
MyData myData = new MyData();
string[] words = line.Split(";");
myData.ID = words[0];
myData.Name = word[1];
myData.Age = words[2];
myData.Date = words[3];
myData.Score = words[4];
//Do something...
myDataList.Add(myData);
}
StringBuilder sb = new StringBuilder();
foreach (string data in myDataList)
{
sb.AppendLine(string.Format("{0},{1},{2},{3},{4}",
data.ID,
data.Name,
data.Age,
data.Date,
data.Score));
}
File.WriteAllText("output.txt", sb.ToString(), Encoding.ASCII);
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我在ansii中获得output.txt文件,但没有使用瑞典语字符.有人可以帮助我知道如何将文件数据从UTF-8保存到Ansii?谢谢.
我有一个方法,我想概括.我想对任何对象类型使用以下Deserialize函数,如belew:
ExportDefinition _expDefinition = new ExportDefinition("a.ini");
DeliveryDefinition _delDefinition = new DeliveryDefinition("b.ini");
ExportDefinition expDef = Deserialize(_expDefinition);
DeliveryDefinition devDef = Deserialize(_delDefinition);
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public SomeType Deserialize(SomeType?? tp) // What should I use instead of SomeType?
{
try
{
FileStream readFileStream = new FileStream(definitionFile, FileMode.Open, FileAccess.Read, FileShare.Read);
XmlSerializer serializerObj = new XmlSerializer(typeof(tp));
tp loadedObj = (tp)serializerObj.Deserialize(readFileStream);
readFileStream.Close();
}
catch (Exception ex)
{
throw new Exception(ex.Message);
}
return loadedObj;
}
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任何想法,如何实现这一目标?
如何将两个SQL查询合二为一?
SELECT *FROM table1 WHERE chapter=88 AND sentence>=23
SELECT *FROM table1 WHERE chapter=89 AND sentence>=1 AND sentence<=23
Run Code Online (Sandbox Code Playgroud) 我在设计师中编辑过一张桌子.但是当我编写查询时,它不会在上下文菜单中显示列.有人能帮助我理解为什么吗?