小编Lio*_*elF的帖子

我有这样的集合:

{ 
  "_id":"1321464"
  "Sex":"Male"
  "Age":"20" 
  "City":"Toronto" #Maybe this field are not present.
}

我想找到我所有的文件"City"字段不存在.我尝试:

collection.find({"sex":"Male"},{"City":{"$exists": False}},{'Age': 1, '_id':0})

我有这个错误信息:

File "/usr/local/lib/python2.7/dist-packages/pymongo/collection.py", line 1239, in find
    return Cursor(self, *args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/pymongo/cursor.py", line 125, in __init__
    raise TypeError("skip must be an instance of int")
TypeError: skip must be an instance of int

我有一个 WooCommerce 商店，我销售许多产品，每个产品只有 1 件。

销售唯一数量的产品后，我自动显示“缺货”，但我想将此产品页面重定向到自定义页面。

我搜索了很多小时的插件 => 没有。

你有解决办法吗？

谢谢。

I have a script and I want to remove u'domain' and u from the list

from pymongo import MongoClient


client = MongoClient()
db = client.domains
collection = db.domain
find_document = collection.find({},{'domain': 1, '_id':0})

data = list(find_document.limit(2))

{myIds.push(myDoc.domain.str)})
print (data)

The result is :

[{u'domain': u'allegacyhsa.org'}, {u'domain': u'americanhelpinghands.org'}]

I want to print only the domain like :

['allegacyhsa.org','americanhelpinghands.org']

Without u and {

Thank you in advance for your answer.