小编amj*_*amj的帖子

我已经为我的android Activity类添加了一些本机方法.现在我想为它创建头文件class.

从命令行创建头文件时出现以下错误.

C:\AndroidProjects\JniTest\bin\classes>javah -classpath .;
C:\adt-bundle-windows-x86\sdk\platforms\android.jar com.example.jnitest.JniTest
Error: cannot access android.app.Activity
class file for android.app.Activity not found

基本上无法从jar访问活动类.

请指教.

可能重复:
活动上下文和应用程序上下文之间的差异

何时使用Context和Activity.我已经阅读了使用Context和Activity作为参数的代码,如下面的构造函数,请在此清除我

public AmazedView(Context context, Activity activity) {
        super(context);

        mActivity = activity;

        // init paint and make is look "nice" with anti-aliasing.
        mPaint = new Paint();
        mPaint.setTextSize(14);
        mPaint.setTypeface(mFont);
        mPaint.setAntiAlias(true);

        // setup accelerometer sensor manager.
        mSensorManager = (SensorManager)                activity.getSystemService(Context.SENSOR_SERVICE);
        // register our accelerometer so we can receive values.
        // SENSOR_DELAY_GAME is the recommended rate for games
        mSensorManager.registerListener(mSensorAccelerometer, SensorManager.SENSOR_ACCELEROMETER,
                SensorManager.SENSOR_DELAY_GAME);

        // setup our maze and marble.
        mMaze = new Maze(mActivity);
        mMarble = new Marble(this);

        // load array from /res/values/strings.xml
        mStrings = …

我在15天前在Google Play上发布了一个应用程序,我对该应用程序进行了一些修改,现在我想再次发布它.

当我尝试在不更改VersionCode ="1"的情况下上传apk时,Google Developers Console给了我一个错误:已经存在versionCode ="1"的应用程序.

然后我尝试将版本代码更改为2并导出apk,遗憾的是,VersionCode始终会恢复为"1".

请帮忙解决这个问题.

我正在尝试创建一个自定义编辑文本,并在这里陷入困境......

请参阅下面的代码

public class MainActivity extends Activity {

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.activity_main, menu);
    return true;
}


public static  class MyEditText1 extends EditText{

    Paint mPaint;




    public MyEditText1(Context context) {
        super(context);
        // TODO Auto-generated constructor stub

    }

    public MyEditText1(Context context, AttributeSet attrs) {
        super(context, attrs);
        mPaint=new Paint();
        mPaint.setColor(Color.BLACK);


    }

    @Override
    protected  void onDraw(Canvas c){
        super.onDraw(c);
        int height=getHeight();
        int width=getWidth();
        int linespace=10;
    int count=height/linespace;

        for(int i=0;i<count;i++){
            c.drawLine(0, i*linespace, width, i*linespace, mPaint); …

从设置线程状态的角度来看,我不清楚这两种方法.

Java Docs说Thread.interrupt()设置线程中断状态标志并调用Thread.interrupted()方法给出线程的状态并清除标志.

当这在真实场景中使用时.. ??