我使用lite Converter将我的pb格式模型转换为tflite格式，并使用lite Interpreter运行这个模型，但是效果不好，报错是：
Traceback (most recent call last):
File "/home/yuan/anaconda3/envs/TFLite/lib/python3.7/threading.py", line 917, in _bootstrap_inner
self.run()
File "/home/yuan/tensorflow-master/tensorflow/examples/speech_commands/audio/audio_processor_lite.py", line 41, in run
self._interpreter.allocate_tensors()
File "/home/yuan/anaconda3/envs/TFLite/lib/python3.7/site-packages/tensorflow_core/lite/python/interpreter.py", line 198, in allocate_tensors
return self._interpreter.AllocateTensors()
File "/home/yuan/anaconda3/envs/TFLite/lib/python3.7/site-packages/tensorflow_core/lite/python/interpreter_wrapper/tensorflow_wrap_interpreter_wrapper.py", line 106, in AllocateTensors
return _tensorflow_wrap_interpreter_wrapper.InterpreterWrapper_AllocateTensors(self)
RuntimeError: Regular TensorFlow ops are not supported by this interpreter. Make sure you invoke the Flex delegate before inference.Node number 0 (FlexAudioSpectrogram) failed to prepare.
看起来 lite 还不支持 FlexAudioSpectrogram 操作。但是当我使用speech command android demo提供的tflite模型时，效果很好。所以我想知道这个模型是如何转换的？
我尝试上传包含 1000 条用户记录的 Excel 表格。我试图向 w 用户发送一个临时密码，在某些情况下它成功了，在其他情况下我收到错误432 4.3.2 STOREDRV.ClientSubmit;发送者线程限制超过你能帮助解决这个问题吗？
我正在尝试上传文件，但多部分文件未正确传递。
这是我的控制器，我正在尝试添加一些文件。仅返回 @RequestParam，Arrays.asList(files) 返回一个空数组。我将添加下面打印行的结果。
@Transactional
@RequestMapping(path = "/profile/files", method=RequestMethod.POST)
@ApiResponses(value = {
@ApiResponse(code = HttpServletResponse.SC_BAD_REQUEST, message = "Wrong file type", response = ErrorResponse.class),
@ApiResponse(code = HttpServletResponse.SC_FORBIDDEN, message = "Not authorized", response = ErrorResponse.class),
@ApiResponse(code = HttpServletResponse.SC_INTERNAL_SERVER_ERROR, message = "Internal Error", response = InternalErrorResponse.class)
})
@ResponseBody
@ApiOperation(
value = "Add files",
tags = "Users"
)
public List<FileDto> addProfilePicture(@RequestParam("file") MultipartFile[] files) {
System.out.println("Controller: Files from params: " + files.toString());
List<MultipartFile> filesToAdd = Arrays.asList(files);
System.out.println("Controller: Files Array.asList: " + filesToAdd);
List<File> savedFiles = …我们需要为netbeans的本地电影院完成一个简单的票务系统，而我为两个问题感到困惑。
问题1作为输出的一部分，一旦您选择了票证类型+数量，就需要有一个输出“您正在购买Y数量的X张票证”
问题2是长者票需要花费$ 32.50，我似乎无法找到一种允许使用小数进行计算的解决方法。我进行了调试，似乎将数字更改为整数，然后该整数将无法正确计算。救命！
package ticketingsystem;
import java.io.*;
public class ticketingsystem
{
public static void main(String []args) throws Exception
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String order,again;
int quantity,price1=0,price2=0, price3=0,loop1=0,quantity1,quantity2=0;
System.out.println(" ");
System.out.println("Welcome to the cinemas!");
System.out.println(" ");
System.out.println("MAIN MENU");
System.out.println(" ");
System.out.println("The cinema has the following options");
System.out.println(" ");
System.out.println("1 = Child (4-5 yrs)");
System.out.println("2 = Adult (18+ yrs)");
System.out.println("3 = Senior (60+ yrs)");
do{
System.out.println(" ");
System.out.print("Enter your option: ");
order=br.readLine();
if (order.equalsIgnoreCase("1")) {
price1=18;
} else if (order.equalsIgnoreCase("2")) …嗨，我有一个关于在Scala中验证列表的问题。我有一个看起来像这样的方法：
def validate(item: Item): Try[Unit] = {
if (item.isValid) Success(())
else Failure(new isNotValidException("not valid"))
}
现在我正在使用这种方法来验证itemList: List[Item]如下：
def listIsValid(list: List[Item]): Try[Unit] = {
list
.map(validate(_))
.collectFirst{ case f @ Failure(_: Exception) => f }
.getOrElse(Success(()))
}
我最终想解决的问题Try[Unit]（如果所有项目均有效，则为成功，如果至少一项无效，则为失败。
这是验证列表中所有项目的好方法吗？还是有更好的方法来验证列表中的项目？它应该很快就会失败，如果一项失败了，我就不需要知道当时其他项是否无效。列表验证用于的理解，最终需要Try[Unit]再次解析为单个
嗨，我想使用植物 uml制作一个像这样具有一些并行交互的 uml 图。
但我不知道是否可以在“线程”之间添加虚线。到目前为止我所拥有的是以下内容。A正在发送的东西，被拾起，并采取行动的b，c并d在同一时间。是否可以在b,c和之间添加虚线d？
group par
activate a
a -> b: doSomething
a -> c: doSomething
a -> d: doSomething
end
我正在尝试检查数组中是否已使用名称，但是它仅适用于现货[0]。我假设它从布尔中的for循环仅经历一次并且不递增以检查其他点？
试图改变不同的if和while循环
if (depotCount < 4){ // Runs if the depots are less than 4
System.out.println("Enter your depots name");
name = console.next().toLowerCase();
if (check(depots, name) == true){
System.out.println("Depot name already exists");
break;
}
else {
addDepot(depots, name);
}
} else {
System.out.println("Only 4 depots are allowed");
break;
}
public boolean check(Depot [] depots, String name){
boolean check = false;
for (int i = 0; i < depots.length; i++){
if(depots[i].getDepotName().equals(name))
return true;
else {
return false;
}
}
return check;
} …Hello i came along this question where the author wanted to convert the String:
exampleString = "2 Marine Cargo 14,642 10,528 Denver Factory North 16,016 more text 8,609 argA 2,106 argB"
into an array / list that looks similar to this:
String[] resultArray = {"2", "Marine Cargo", "14,642", "10,528", "Denver Factory North", "16,016",
"more text", "8,609", "argA", "2,106", "argB"};
So numeric parts (with or without a comma) are considered an element
and pure alpha sequences (divided by none, one or …
我试图在此仓库中运行导入的项目
但是我得到了这个错误：
Unable to find method 'org.gradle.api.tasks.SourceSetOutput.getClassesDir()Ljava/io/File;'.
Possible causes for this unexpected error include:
Gradle's dependency cache may be corrupt (this sometimes occurs after a network connection timeout.)
Re-download dependencies and sync project (requires network)
The state of a Gradle build process (daemon) may be corrupt. Stopping all Gradle daemons may solve this problem.
Stop Gradle build processes (requires restart)
Your project may be using a third-party plugin which is not compatible with the other plugins in the …How does string concatenation work here?
As the return value is of type String here, so everything should be converted to string. But why is it printing "30Good3040morning" here, instead of "1020Good3040morning". Please Help.
class StringConcatinationWorking{
public static void main(String ...args){
String s1 = 10 + 20 + "Good" + 30 + 40 + "morning";
System.out.println(s1);
}
}