小编ims*_*i17的帖子

试图解决问题，但是Hackerrank的编译器在解析时不断抛出错误EOFError：不知道哪里出错了。

#!usr/bin/python

b=[]
b=raw_input().split()
c=[]
d=[]
a=raw_input()
c=a.split()
f=b[1]
l=int(b[1])
if(len(c)==int(b[0])):          
    for i in range(l,len(c)):
        d.append(c[i])
        #print c[i]
    for i in range(int(f)):
        d.append(c[i])
        #print c[i]
for j in range(len(d)):
    print d[j],

我也尝试尝试抓住解决它，但随后没有输入。

try:
    a=input()
    c=a.split()
except(EOFError):
    a=""

输入格式是2个间隔开的整数，然后是数组

追溯错误是：

Traceback (most recent call last):
  File "solution.py", line 4, in <module>
    b=raw_input().split()
EOFError: EOF when reading a line

#!/usr/bin/python\n# -*- coding: utf-8 -*-\n\nimport re\nseparators = [u"\xe0\xa5\xa4", u",", u"."]\ndat=open(r"C:\\Users\\User\\Desktop\\text4.txt",\'r\').read()\ntext=dat.decode("utf-8")\nwros=text.split()\nout=""\nimport string\nspace=" "\ncounter=0;\nfor word in wros:\n        out=u" ".join(word)\n\nwrit=open("C:\\\\Users\\\\User\\\\Desktop\\\\text5.txt",\'w\')\nwrit.write(out.encode(\'utf-8\'))\nwrit.close()\n

text4.txt 包含 \xe0\xa4\xad\xe0\xa4\xbe\xe0\xa4\xb0\xe0\xa4\xa4 \xe0\xa4\x95\xe0\xa4\xbe \xe0\xa4\x87\xe0\xa4 \xa4\xe0\xa4\xbf\xe0\xa4\xb9\xe0\xa4\xbe\xe0\xa4\xb8 \xe0\xa4\x95\xe0\xa4\xbe\xe0\xa4\xab\xe0\xa5\x80 \xe0\xa4\xb8\xe0\xa4\xae\xe0\xa5\x83\xe0\xa4\xa6\xe0\xa5\x8d\xe0\xa4\xa7\xe0\xa4\x8f\xe0\xa4\xb5\xe0 \xa4\x82 \xe0\xa4\xb5\xe0\xa4\xbf\xe0\xa4\xb8\xe0\xa5\x8d\xe0\xa4\xa4\xe0\xa5\x83\xe0\xa4\xa4\xe0\xa4 \xb9\xe0\xa5\x88\xe0\xa5\xa4\ntext5.txt 输出为 \xe0\xa4\xb9 \xe0\xa5\x88 \xe0\xa5\xa4

所需的输出为 \xe0\xa4\xad\xe0\xa4\xbe\xe0\xa4\xb0\xe0\xa4\xa4 \xe0\xa4\x95\xe0\xa4\xbe \xe0\xa4\x87\xe0\xa4\ xa4\xe0\xa4\xbf\xe0\xa4\xb9\xe0\xa4\xbe\xe0\xa4\xb8\xe0\xa4\x95\xe0\xa4\xbe\xe0\xa4\xab\xe0\xa5\x80 \ xe0\xa4\xb8\xe0\xa4\xae\xe0\xa5\x83\xe0\xa4\xa6\xe0\xa5\x8d\xe0\xa4\xa7\xe0\xa4\x8f\xe0\xa4\xb5\xe0\ xa4\x82\xe0\xa4\xb5\xe0\xa4\xbf\xe0\xa4\xb8\xe0\xa5\x8d\xe0\xa4\xa4\xe0\xa5\x83\xe0\xa4\xa4\xe0\xa4\ xb9\xe0\xa5\x88\xe0\xa5\xa4

请告诉我我所做的事情是错误的？\n需要帮助！提前致谢