我有下表:
select * from top3art;
path | count
-----------------------------+--------
/article/candidate-is-jerk | 338647
/article/bears-love-berries | 253801
/article/bad-things-gone | 170098
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我想在路径值中删除'/ article /',所以我这样做:
select *, trim(leading '/article/' from path) from top3art;
path | count | ltrim
-----------------------------+--------+--------------------
/article/candidate-is-jerk | 338647 | ndidate-is-jerk
/article/bears-love-berries | 253801 | bears-love-berries
/article/bad-things-gone | 170098 | bad-things-gone
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第2行和第3行工作正常.但是第一排发生了什么?它修剪了'/ article/ca'.为什么还需要2个字符?
现在看看当我修剪'/ articl'时会发生什么:
select *, trim(leading '/articl' from path) as test from top3art;
path | count | test
-----------------------------+--------+----------------------
/article/candidate-is-jerk | 338647 | e/candidate-is-jerk
/article/bears-love-berries | 253801 | e/bears-love-berries …Run Code Online (Sandbox Code Playgroud)