小编J. *_*ith的帖子

我想根据迭代创建一个case语句,但我理解case表达式必须是常量.这是一个什么解决方法？

我尝试了下面的代码,但它仍然无法正常工作.

#include <iostream>
using std::cout;
using namespace std;

int main()
{
    int i = 0;
    while( i >= 0)
    {
        const int z = i;
        cout << "Enter a number other than " << z << "!\n";
        int choice;
        cin >> choice;
        switch(choice){
            case z: cout << "Hey! you weren't supposed to enter "<< z <<"!"; return 0; break;
            default: if(i==10)
                    {
                        cout << "Wow, you're more patient then I am, you win."; return 0;
                    }
                    break;
        }
        i++; …