我有这样简单的表格:
+----------+---------------+-------------+
| ID (int) | KEY (varchar) | VALUE (int) |
+----------+---------------+-------------+
| 1 | asdf | 100 |
| 2 | fdsa | 321 |
| 3 | ecda | 211 |
+----------+---------------+-------------+
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我想更新行,KEY = 'something'但如果没有KEY = 'something'我想要INSERT新行的行:
+----------+---------------+-------------+
| ID (int) | KEY (varchar) | VALUE (int) |
+----------+---------------+-------------+
| 1 | asdf | 100 |
| 2 | fdsa | 321 |
| 3 | ecda | 211 |
| …Run Code Online (Sandbox Code Playgroud) 当我使用urllib2模块不在函数中一切正常(这里是代码):
headers = {'User-Agent' : 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/535.7 (KHTML, like Gecko) Chrome/16.0.912.77 Safari/535.7'}
request = urllib2.Request(url, '', headers)
response = urllib2.urlopen(request)
returned_array = [response.geturl(), response.read()]
print returned_array
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但当我把它用于功能:
def nk_get_site(url):
headers = {'User-Agent' : 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/535.7 (KHTML, like Gecko) Chrome/16.0.912.77 Safari/535.7'}
request = urllib2.Request(url, '', headers)
response = urllib2.urlopen(request)
returned_array = [response.geturl(), response.read()]
return returned_array
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它不工作,错误:
Traceback (most recent call last):
File "C:\py\NetKit\netkit.py", line 37, in <module>
print nk_get_site('http://www.google.com/')
File "C:\py\NetKit\netkit.py", line 33, in nk_get_site …Run Code Online (Sandbox Code Playgroud) 我有这个非常简单的汇编代码:
start:
add ax, 100
; if ax overflow add to bx 1
jmp start
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但我不知道如何检测ax寄存器溢出,任何人都可以帮助我吗?
我正在使用Sublime Text 2,当我双击与下划线连接的单词时:
this_is_it
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它会自动选择整个短语,但是当单词与break符号连接时,如下所示:
this-is-it
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它只会选择一个单词,如何设置Sublime Text来选择整个短语?
我试图在我的类构造函数中初始化指向struct数组的指针,但它根本不起作用...
class Particles {
private:
struct Particle {
double x, y, z, vx, vy, vz;
};
Particle * parts[];
public:
Particles (int count)
{
parts = new Particle [count]; // < here is problem
}
};
Run Code Online (Sandbox Code Playgroud) 我正在尝试检测设备当前是否正在充电,但此代码始终将isCharging变量设置为false:
public class PowerReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent)
{
int status = intent.getIntExtra(BatteryManager.EXTRA_STATUS, -1);
boolean isCharging = status == BatteryManager.BATTERY_STATUS_CHARGING || status == BatteryManager.BATTERY_STATUS_FULL;
int chargePlug = intent.getIntExtra(BatteryManager.EXTRA_PLUGGED, -1);
boolean usbCharge = chargePlug == BatteryManager.BATTERY_PLUGGED_USB;
boolean acCharge = chargePlug == BatteryManager.BATTERY_PLUGGED_AC;
if (isCharging)
{
Toast.makeText(context, "Charging", Toast.LENGTH_LONG).show();
} else {
Toast.makeText(context, "Not charging", Toast.LENGTH_LONG).show();
}
}
}
Run Code Online (Sandbox Code Playgroud) 我有这样的列表:
[['one', 'two', 'three', ...], ['a', 'b', ...], ['left', 'right'] ...]
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我需要创建所有可能的项目组合并将其放入字符串中:
"one|a|left"
"one|a|right"
"one|b|left"
"one|b|right"
"two|a|left"
"two|a|right"
"two|b|left"
...
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最简单的方法是什么?
android ×2
python ×2
assembly ×1
c++ ×1
function ×1
list ×1
mysql ×1
overflow ×1
php ×1
python-3.x ×1
sql ×1
sublimetext ×1
sublimetext2 ×1
urllib2 ×1