小编Can*_*tin的帖子

当我尝试在dequeue()函数中为Student的name字段释放char数组时,程序崩溃了.内存先前已在createStudent()函数中分配.

我真的看不出我想念的东西.

#include "iostream"
#include "stdio.h"
using namespace std;

struct Student
{
    int id;
    char* name;
};

struct QueueNode
{
    Student* info;
    QueueNode* next;
};

Student* createStudent(int id, char* name)
{
    Student* s = (Student*)malloc(sizeof(Student));
    s->id = id;
    s->name = (char*)malloc(sizeof(name) + 1);
    strcpy(s->name, name);

    return s;
}

QueueNode* createQueueNode(Student *s)
{
    QueueNode *queue = (QueueNode*)malloc(sizeof(QueueNode));
    queue->info = s;
    queue->next = nullptr;

    return queue;
}

void enqueueNode(QueueNode* &root, QueueNode* node)
{
    if (root == nullptr)
        root = node;
    else
    { …

如果接口不应该在C#中具有属性,那么如何在接口中拥有属性,因为属性是属性的getter和setter？在类中我们有这个例子,我认为接口应该只有方法声明.

interface IKnownProgrammingLanguages
{
    string[] ProgrammingLanguages { get; set; }
}