我在Parcelable对象中有一个可序列化的对象(ArrayList)。我正在尝试读取可序列化的对象,但在读取后无法弄清楚如何精确地重建它:
public class WifiAP implements Parcelable {
public String _mac;
public String _mac2;
public String _ssid;
public boolean _dualband;
public int _band; // kilohertz
public int _band2;
ArrayList<Integer> _rssis;
public Packet _beacon;
public void writeToParcel(Parcel out, int flags) {
out.writeString(_mac);
out.writeString(_mac2);
out.writeString(_ssid);
if(_dualband)
out.writeInt(1);
else
out.writeInt(0);
out.writeInt(_band);
out.writeInt(_band2);
out.writeSerializable(_rssis);
}
private WifiAP(Parcel in) {
_mac = in.readString();
_mac2 = in.readString();
_ssid = in.readString();
if(in.readInt()==1)
_dualband=true;
else
_dualband=false;
_band = in.readInt();
_band2 = in.readInt();
_rssis = in.readSerializable(); // help here, this …
Run Code Online (Sandbox Code Playgroud) 我有一个Network类,我想要两个虚拟函数,我将要重载:airtime()
和airtime(std::vector<int> freq_bins)
;
我定义了类,以及底部的函数:
class Network
{
public:
// Properties of the network protocol
std::string _name;
std::vector<float> _channels;
float _bandwidth;
float _txtime;
// Properties of the specific network
int _id;
macs::mac_t _mac;
protocols::protocol_t _protocol;
bool _static;
float _desired_airtime;
float _act_airtime;
bool _active;
// Constructor
Network();
virtual float airtime() { };
virtual float airtime(std::vector<int> freq_bins) { };
};
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现在,我有一个我想要重载它们的第二个类.这是这个类的标题:
#ifndef _CSMA_H_
#define _CSMA_H_
#include <string>
#include <vector>
#include <map>
#include "MACs.h"
#include "Protocols.h"
#include "Network.h"
class CSMA : …
Run Code Online (Sandbox Code Playgroud) 我正在使用LINQ执行自定义查询,它根据我的语句返回一个匿名类型列表:
var currUnitFaster = (from unit in pacificRepo.Units
join loc in pacificRepo.GeoLocations on new { unit.geo_location.Latitude, unit.geo_location.Longitude } equals new { loc.geo_location.Latitude, loc.geo_location.Longitude }
join st in pacificRepo.UnitStatuses on unit.c_number equals st.c_number
select new {
index = "0",
unit.c_number,
unit.serial_number,
unused = "0",
unit.ip_address,
unit.build_version,
status = (st.status == Pacific.Domain.Entities.UnitStatus.Statuses.COMPLETE) ? "<font color=\"green\">" + st.stage + "</font>" : "<font color=\"red\">" + st.stage + "</font>",
location = (loc==null) ? "Unknown" : loc.city + ", " + loc.state_abbrv,
unit.location_at_address,
latitude = unit.geo_location.Latitude, …
Run Code Online (Sandbox Code Playgroud) 有没有一种很好的方法n
可以使用矩阵运算加速这个matlab代码块(特别是可能很大)?超过1/4的执行时间是在这个小代码块中.
% Get the bin indexes that we will place the network in
bins = [];
for n=low_freq:0.5:high_freq;
bins = [bins, (n-spec_start)/spec_bin_size+1];
end
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测试代码:
spec_start=2400
spec_bin_size=0.5
low_freq = 2437
high_freq=2438
bins = [];
for n=low_freq:0.5:high_freq;
bins = [bins, (n-spec_start)/spec_bin_size+1];
end
bins % 75 76 77
bins = [];
bins = (low_freq:0.5:high_freq - spec_start)./spec_bin_size + 1;
bins % empty?
Run Code Online (Sandbox Code Playgroud) 我试图通过使用排序谓词为类指针向量创建自定义排序:
struct sort_by_airtime
{
inline bool operator() (const Network *n1, const Network *n2)
{
return (n1->airtime() < n2->airtime());
}
};
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对于每个网络,我们按airtime()返回的float进行排序.
现在,我尝试使用如下:
std::vector<Network *> Simulator::sort_networks(std::vector<Network *> netlist, bool sort_airtime) {
std::vector<Network *> new_netlist = netlist;
if(sort_airtime) {
sort(new_netlist.begin(), new_netlist.end(), sort_by_airtime());
}
}
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但是,我得到了很多这样的错误:
In file included from Simulator.cpp:7:
Simulator.h: In member function ‘bool Simulator::sort_by_airtime::operator()(const Network*, const Network*)’:
Simulator.h:48: error: passing ‘const Network’ as ‘this’ argument of ‘virtual float Network::airtime()’ discards qualifiers
Simulator.h:48: error: passing ‘const Network’ as ‘this’ argument of …
Run Code Online (Sandbox Code Playgroud) 我认为我误解了小组如何在正则表达式和C#中工作.但是,我仍然想知道我想要的是否可能.
我们采取以下字符串
:::name(uploadFileName)
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哪个与表达式匹配
\A:::[a-zA-Z0-9_-]+\([a-zA-Z0-9_-]+\)
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我希望能够做的就是方便地提取出来像什么property = name
,然后value = uploadFileName
.
我认为,这将与组,其中发生match.Groups[0].Value
会name
和match.Groups[1].Value
会uploadFileName
.根据群体的定义,我认为这是真的:
分组构造描述正则表达式的子表达式并捕获输入字符串的子字符串.
但是,match.Groups[0].Value
简直就是整个字符串:::name(uploadFileName)
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