这是我的javascript
function ajax_post(){
// Create our XMLHttpRequest object
var hr = new XMLHttpRequest();
// Create some variables we need to send to our PHP file
var url = "LiveUpdate.php";
var sb = document.getElementById("LiveUpdate").value;
var FirstName = document.getElementById("FirstName").value;
var images = document.getElementById("images").value;
var vars = "update="+sb+"&FirstName="+FirstName+"&images="+images;
hr.open("POST", url, true);
// Set content type header information for sending url encoded variables in the request
hr.setRequestHeader("Content-type", "multipart/form-data");
// Access the onreadystatechange event for the XMLHttpRequest object
hr.onreadystatechange = function() {
if(hr.readyState == 4 …
Run Code Online (Sandbox Code Playgroud)