小编San*_*ndo的帖子

我想在列表中显示所有本机联系人,并让用户将列表中的联系人(多个联系人)添加到我的应用程序数据库.如何使用这个可以让任何人给我构思或分享一些代码..在此先感谢..

这是我的代码

     Log.i("sdfgsdf", time.toGMTString());
        String SENT = "SMS_SENT";
        Intent y=  new Intent(SENT);
        y.putExtra("number", phoneNumber);
        y.putExtra("time", time.toString());

        String DELIVERED = "SMS_DELIVERED";
        int FLAG_UPDATE_CURRENT =(0x08000000) ;
        PendingIntent sentPI = PendingIntent.getBroadcast(this, 0,
        y, FLAG_UPDATE_CURRENT);

        PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
        new Intent(DELIVERED), FLAG_UPDATE_CURRENT);

        //---when the SMS has been sent---
        r=  new BroadcastReceiver(){
            @Override
             public void onReceive(Context arg0, Intent arg1) {

                switch (getResultCode())
                {

                    case Activity.RESULT_OK:
                        Toast.makeText(getBaseContext(), "SMS sent"+arg1.getStringExtra("number"), 
                                Toast.LENGTH_SHORT).show();
                        Constant.DB = Compose.this.openOrCreateDatabase("Indigo",MODE_PRIVATE, null);
                        Constant.DB.execSQL("UPDATE Message SET IsMsgSent='true' where DateAndTime='" + arg1.getStringExtra("time") + "' and ContactNumber='"+arg1.getStringExtra("number")+"'"); …

这是我使用的代码

    private String getContactNameFromNumber(String number) {
        // define the columns I want the query to return
        String[] projection = new String[] {
                Contacts.Phones.DISPLAY_NAME,
                Contacts.Phones.NUMBER };

        // encode the phone number and build the filter URI
        Uri contactUri = Uri.withAppendedPath(Contacts.Phones.CONTENT_FILTER_URL, Uri.encode(number));

        // query time
        Cursor c = getContentResolver().query(contactUri, projection, null,
                null, null);

        // if the query returns 1 or more results
        // return the first result
        if (c.moveToFirst()) {
            String name = c.getString(c
                    .getColumnIndex(Contacts.Phones.DISPLAY_NAME));
            return name;
        }

        // return the original …

什么是Lua Scripting？我在哪里可以学到它？我想用Lua开发Android游戏,我该如何开始并且可以在Android中使用Lua ..？