我想在阿基米德螺旋上创建一个条形图,就像这里讨论的那样.

最终目标是这样的,但不那么压倒性.

这是一个示例数据帧:

    test <- structure(list(month = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12,
                                     1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12), 
           year = c(2015, 2015, 2015, 2015, 2015, 2015, 2015, 
                    2015, 2015, 2015, 2015, 2015, 2016, 2016, 
                    2016, 2016, 2016, 2016, 2016, 2016, 2016, 
                    2016, 2016, 2016), 
           value = c(49, 34, 35, 34, 50, 35, 48, 50, 44, 38, 42, 
                   43, 33,30, 42, 43, 58, 55, …

我有数年有关个人的数据，但是他们的姓名每年的格式不同。名称中的一半已经按“ First Last”顺序排列，但是我不知道如何成功编辑另一半（“ Last，First”）。

这是样本df：

name <- c("First1 Last1","Last2, First2", "Last3, First3", "First4 Last4", "First5 Last5")
salary <-c(51000, 72000,125000,67000,155000)
year <-c(2012,2014,2013,2013,2014)

df <- data.frame(name, salary, year, stringsAsFactors=FALSE)

这是我尝试过的方法：用逗号分隔文本：

df$name2 <- strsplit(df$name, ", ") #to split the character string by comma
df$name3 <-paste(df$name2, collapse=" ") #to collapse the newly created vectors back into a string
df$name4 <-paste(rev(df$name2)) #to try pasting each vector in reverse order
df$name5 <-paste(rev(df$name2)[2:1]) #trying again...

我已经打印了正确的名称，但是倒退了，并且将它们打印在错误的行上，但是尽管进行了谷歌搜索，但我仍然无法正常工作。我究竟做错了什么？

好消息：我可以使用树状图包创建一个漂亮的树状图。

数据：

forTm <- structure(list(
  UnitGroup = c("1N", "BHU", "CSU", "ED", "Med/Surg", "Med/Surg", "Telemetry", 
            "Telemetry", "Telemetry", "Telemetry", "Telemetry"), 
  Unit = c("A", "B", "C", "ED", "D", "E", "F", "G", "H", "I", "J"),
  Count = c(1L, 1L, 1L, 1L, 15L, 10L, 5L, 2L, 3L, 8L, 4L)), 
  class = c("data.frame"), 
  row.names = c(NA, -11L),
  .Names = c("UnitGroup", "Unit", "Count"))

树形图：

library(treemap)
tm <- treemap(forTm,
          index = c("UnitGroup", "Unit"),
          vSize = "Count",
          vColor = "Count",
          type = "dens",
          palette = "YlGnBu",
          title = "# …