小编HRg*_*ger的帖子

我使用Spring创建了一个Web服务.在我的嵌入式tomcat服务器上运行它时工作正常.但是,当我将其打包为JAR文件并使用java -jar命令运行它时,我收到此异常.

我的服务发送一个简单的soap请求,服务器响应是:

 "exception": "java.lang.NoClassDefFoundError",
    "message": "javax/xml/soap/SOAPException",

这是我在邮差中得到的回应.

任何我可以寻找问题的想法.

我正在尝试使用以下代码发送短信:

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLEncoder;
import java.util.Iterator;
import java.util.Vector;

public class SMS {

    public static void send(String uid, String pwd, String phone, String msg)
            throws Exception {

        if ((uid == null) || (uid.length() == 0)) {
            throw new IllegalArgumentException("User ID should be present.");
        }

        uid = URLEncoder.encode(uid, "UTF-8");

        if ((pwd == null) || (pwd.length() == 0)) {
            throw new IllegalArgumentException("Password should be present.");
        }

    pwd = URLEncoder.encode(pwd, "UTF-8");

        if ((phone …

我正在阅读Oreilly Java Programming with Oracle JDBC edition,我注意到有一个使用java.util.properties对象的例子,如下所示;

public class Connector {


    Connection con = null;
    private Properties info = new Properties();

    public void connect(){
        info.put("user", "sys as sysdba");
        info.put("password", "testpass");
        String driverName = "oracle.jdbc.driver.OracleDriver";

        try {
            Class.forName(driverName);
        } catch (ClassNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }


        String serverName = "localhost";
        String port = "1521";
        String sid = "XE";
        String url = "jdbc:oracle:thin:@" + serverName + ":" + port + ":" + sid;



        try {
            con …