随身携带以下 RSA 私钥,我必须使用RS256 算法生成 JWT 令牌。
这是我的示例私钥:
-----BEGIN RSA PRIVATE KEY----- /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-----END RSA PRIVATE KEY-----
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标题
{
"alg": "RS256",
"typ": "JWT"
}
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身体:
{
"iss": "14a2fecb-ddd7-4823-46e2-67515bc01734",
"sub": "13f7982d-1f78-46e2-4823-3273568fce89",
"iat": 1521132568,
"exp": 1522136156,
"aud": "account-d.example.com",
"scope": "signature"
}
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下面是我的示例 Java 代码:
package com.knyc.demo;
import java.security.spec.PKCS8EncodedKeySpec;
import org.bouncycastle.util.encoders.Base64;
import org.mule.api.MuleEventContext; …
Run Code Online (Sandbox Code Playgroud) 在我的 github 项目中,每当有东西被推送到 master 分支时,我都会尝试自动创建一个新版本并将其发布到 NPM。
这个想法
我正在使用 github 操作。我的工作流程文件如下所示:
# This workflow will run tests using node and then publish a package to the npm registry when a release is created
# For more information see: https://help.github.com/actions/language-and-framework-guides/publishing-nodejs-packages
name: Node.js Package
on:
#trigger on every commit to the main branch
push:
branches:
- main
- master
jobs:
build:
runs-on: ubuntu-latest
steps:
- uses: actions/checkout@v2
- uses: actions/setup-node@v1
with:
node-version: 12
- run: npm test
publish-npm:
needs: build …
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从昨晚开始,我在使用 Terraform 将 Web 应用程序部署到 azure 时遇到错误:
Error creating/updating App Service Plan "test-euw-asp" (Resource Group "test-middle-euw-rg"): web.AppServicePlansClient#CreateOrUpdate: Failure sending request: StatusCode=400 -- Original Error: Code="LinkedInvalidPropertyId" Message="Property id '' at path 'properties.hostingEnvironmentProfile.id' is invalid. Expect fully qualified resource Id that start with '/subscriptions/{subscriptionId}' or '/providers/{resourceProviderNamespace}/'."
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看起来它正在“hostingEnvironmentProfile”对象中发送一个空的“id”。
2020-02-25T15:31:56.0433755Z 2020-02-25T15:31:56.041Z [DEBUG] plugin.terraform-provider-azurerm_v1.44.0_x4.exe: {"kind":"Windows","location":"westeurope","properties":{"hostingEnvironmentProfile":{"id":""},"perSiteScaling":false,"maximumElasticWorkerCount":1,"reserved":false,"isXenon":false},"sku":{"name":"S1","tier":"standard","size":"S1","capacity":1},"tags":{}}
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我确实将提供程序版本设置为 1.44.0
provider "azurerm" {
version = "~>1.44.0"
}
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我的地形配置
resource "azurerm_resource_group" "rg" {
name = var.ResourceGroupNameApp
location = "West europe"
}
resource "azurerm_app_service_plan" "asp" {
name = var.asp-name
resource_group_name …
Run Code Online (Sandbox Code Playgroud) 我有一个SQL查询,必须在SQL Server Management Studio中针对多个(15)表运行。
是否可以将多个查询的结果保存到文件中?(.txt,Excel工作表?)
不可能使用并集,因为并非所有表都具有相等数量的行。
查询看起来像这样
select *
from tableA
where main_id in(select id from maintable where date is null and status ='new')
select *
from tableB
where main_id in(select id from maintable where date is null and status ='new')
select *
from tableC
where main_id in(select id from maintable where date is null and status ='new')
select *
from tableD
where main_id in(select id from maintable where date is null and status ='new')
select *
from …
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