是否有可能通过Sublime Text中的方法调用获得PHP方法声明？
// pressing some keys combination should navigate me
// to the method declaration. If it's defined in some other file,
// the file should be opened.
$foo->doSomething();
我试图将MySQLi查询错误转换为异常,但不能 - 只有在连接数据库失败时才会抛出mysqli_sql_exception.
我使用mysqli_report(MYSQLI_REPORT_STRICT)和程序化的MySQLi函数嵌入到自定义包装类中.
前代码:
public function mysqlQuery($SQL) {
$this->Result = mysqli_query($this->DBlink, $SQL);
if($this->Result === false)
throw new MySQLiQueryException($SQL, mysqli_error($this->DBlink), mysqli_errno($this->DBlink));
return $this->Result;
}
问题:是否正常没有警告,查询失败时也不会抛出异常,所以我必须检查mysqli_query()是否返回false？
foo:/opt/bar$ git status
# On branch develop
nothing to commit (working directory clean)
foo:/opt/bar$ git pull --rebase origin develop
From ssh://xxx/yyy
* branch develop -> FETCH_HEAD
First, rewinding head to replay your work on top of it...
Applying: Subscription logging added.
Using index info to reconstruct a base tree...
<stdin>:120: trailing whitespace.
* @return integer
<stdin>:143: trailing whitespace.
* @return integer
<stdin>:166: trailing whitespace.
* @return integer
<stdin>:189: trailing whitespace.
* @return integer
<stdin>:212: trailing whitespace.
* @return integer
warning: …桌子:
CREATE TABLE `T1` (
`UserId` int(10) unsigned NOT NULL,
`FriendUserId` int(10) unsigned NOT NULL,
`IsDisplayed` tinyint(1) unsigned NOT NULL,
`Created` datetime NOT NULL,
KEY `FriendUserId` (`FriendUserId`,`IsDisplayed`,`UserId`,`Created`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
查询:
SELECT `UserId`, `FriendUserId`, UNIX_TIMESTAMP(`Created`) AS `Created`
FROM `T1` WHERE `FriendUserId` = 22
AND `IsDisplayed` = 0
GROUP BY `UserId`
ORDER BY `Created`
EXPLAIN结果:
id: 1
select_type: SIMPLE
table: T1
type: ref
possible_keys: FriendUserId
key: FriendUserId
key_len: 5
ref: const,const
rows: 1
Extra: Using where; Using index; Using temporary; …我有一个体积大小为50GB的ubuntu实例(CRON服务器).我想将它的大小增加到100gb +
以下是我要遵循的步骤,
1)创建连接到CRON服务器的卷的快照.
2)通过指定所需的大小,使用新创建的快照创建卷.在我的情况下100克.
3)通过运行命令分离cron服务器的现有卷
ec2-detach-volume old_volume_id cron_instance_id sda1
4)将新卷(即100gb)附加到cronserver
ec2-attach-volume new_volume_id cron_instance_id sda1
如果丢失或没有使用正确的步骤,请更正.
我只需要支持单一的API格式,即JSON,我不喜欢在我的路由中{_format}.是否可以将其删除？
我正在尝试构建5.6.4-labs-innodb-memcached,但遇到此问题:
# cmake ./
-- MySQL 5.6.4-labs-innodb-memcached
-- Could NOT find Curses (missing: CURSES_LIBRARY CURSES_INCLUDE_PATH)
CMake Error at cmake/readline.cmake:83 (MESSAGE):
Curses library not found. Please install appropriate package,
remove CMakeCache.txt and rerun cmake.On Debian/Ubuntu, package name is libncurses5- dev, on Redhat and derivates it is ncurses-devel.
Call Stack (most recent call first):
cmake/readline.cmake:127 (FIND_CURSES)
cmake/readline.cmake:217 (MYSQL_USE_BUNDLED_LIBEDIT)
CMakeLists.txt:263 (MYSQL_CHECK_READLINE)
-- Configuring incomplete, errors occurred!
安装了libncurses5-dev并设置了CURSES_USE_NCURSES = true,但它没有帮助.有任何想法吗？我已经编译了这个包,但它是在另一台机器上...
编辑:
/var/cache/apt/archives/libncurses5-dev_5.7+20101128-1_i386.deb
/var/lib/dpkg/info/libncurses5.postinst
/var/lib/dpkg/info/libncursesw5.list
/var/lib/dpkg/info/ncurses-base.preinst
/var/lib/dpkg/info/libncursesw5.postrm
/var/lib/dpkg/info/libncursesw5.shlibs
/var/lib/dpkg/info/libncursesw5.md5sums
/var/lib/dpkg/info/libncurses5.symbols
/var/lib/dpkg/info/ncurses-bin.preinst
/var/lib/dpkg/info/ncurses-bin.list
/var/lib/dpkg/info/libncurses5-dev.list
/var/lib/dpkg/info/libncursesw5.symbols
/var/lib/dpkg/info/libncursesw5.postinst …我能够通过@QueryParam()注释获得GET参数,但它看起来只适用于Query String数据:/user?id=123.
/user/123相反,我更喜欢它.为此,我可能会使用@Get("/user/{id}")注释,但我没有看到它有其他元数据@QueryParam():
name="id", requirements="\d+", default="1", description="User id"
如果我使用这两个注释,我会收到一个错误:
ParamFetcher parameter conflicts with a path parameter 'id' for route 'getone'
我的冲突文件块:
/**
* Finds and displays a Users entity.
*
* @Rest\View
* @Rest\Get("/user/{id}")
* @Rest\QueryParam(name="id", requirements="\d+", default="1", description="User id")
* @ApiDoc(section="Partner Users")
* @param int $id
* @return array
*/
PS我需要在path(/user/123)中有一个id ,而不是在查询中,我还需要使用@QueryParam()NelmioApiDocBundle读取它.我该如何解决这个问题？
我正在使用数据表 1.8，它太棒了，我最近阅读了一篇关于数据表列的内联编辑的文章，内联编辑，在这篇关于单击编辑超链接的文章中，数据表列变为文本字段，但我的要求是我必须显示一个下拉列表, 意味着点击编辑超链接它应该被转换成下拉列表并且应该来自我的数据库数据库，并且在保存它的值时被存储到数据库中。这该怎么做？
任何帮助都会对我有很大帮助
我正在将jQuery Mobile与列表视图缩略图集成,但它会将我的图像调整为固定宽度.改变.ui-li-thumb宽度没有帮助.如何让我的拇指更宽？