小编Ger*_*sek的帖子

Laravel Homestead Swift无法发送没有发件人地址的邮件

当我尝试发送密码重置邮件时,我在Laravel 5.1 Homestead中使用库存电子邮件设置收到此错误.

Swift_TransportException in AbstractSmtpTransport.php line 162:Cannot send message without a sender address
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地址填写在app/config/mail.php中:

'from' => array('address' => 'myusername@gmail.com', 'name' => 'hawle'),
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php laravel laravel-5.1

19
推荐指数
5
解决办法
4万
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获取PHPActiveRecord结果作为简单数组,而不是对象数组

我想有一个简单的方法,可以将PHP Activerecord结果作为简单/关联数组,而不是ActiveRecord对象数组.

在Ruby中,我相信这可能是通过.map()方法完成的.(我不是红宝石家伙...)

我想要的是一个简单的方法调用,比如toArray()在Zend_DB_Table中,不是foreach,或类似的东西,但我似乎无法在他们的文档中找到它.

在PHP ActiveRecord中获取结果非常简单:

$settings = SystemSettings::all();
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但它给出了这样的东西:

[0] => SystemSettings Object
    (
        [errors] => 
        [attributes:ActiveRecord\Model:private] => Array
            (
                [param] => author
                [value] => Hawle
            )

        [__dirty:ActiveRecord\Model:private] => Array
            (
            )

        [__readonly:ActiveRecord\Model:private] => 
        [__relationships:ActiveRecord\Model:private] => Array
            (
            )

        [__new_record:ActiveRecord\Model:private] => 
    )

[1] => SystemSettings Object
    (
        [errors] => 
        [attributes:ActiveRecord\Model:private] => Array
            (
                [param] => base_url
                [value] => example.com
            )

        [__dirty:ActiveRecord\Model:private] => Array
            (
            )

        [__readonly:ActiveRecord\Model:private] => 
        [__relationships:ActiveRecord\Model:private] => Array
            (
            )

        [__new_record:ActiveRecord\Model:private] …
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php zend-framework phpactiverecord

6
推荐指数
1
解决办法
7970
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