我想让 Markdown表内的图像具有相同的大小。但是,我拥有的图像资源大小不同。因此我想在表格单元格内设置相对图像大小。
如何在不实际更改图像资源大小的情况下使其Fig 2看起来像?Fig 1
| | | | | |
| :-: | :-: | :-: | :-: | :-: |
| | | | | |
| 180 | 182 | 240 | 250 | 250 |
| <img src="assets/textbooks/180.jpg" width="100%"> | <img src="assets/textbooks/182.jpg" width="100%"> | <img src="assets/textbooks/240.jpg" width="100%"> | <img src="assets/textbooks/250-1.jpg" width="100%"> | <img src="assets/textbooks/250-2.jpg" width="100%"> |
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(相同的代码,但实际图像资源具有相同的大小)
(我目前拥有的)
我想使用从Google Arts & CultureBeautifulSoup检索信息。我检查了许多 stackoverflow 帖子(、、、、、
)
[1],
但
仍然无法检索到信息。[2][3][4][5]
但是,我想要每个图块(图片)的 ( li) 信息,例如 href,find_all并select one返回空列表或无。
您能帮我获取“e0WtYb HpzMff PJLMUc”类锚标记的以下 href 值吗?
href="/entity/claude-monet/m01xnj?categoryId=artist"
以下是我尝试过的。
import requests
from bs4 import BeautifulSoup
url = 'https://artsandculture.google.com/category/artist?tab=time&date=1850'
html = requests.get(url)
soup = BeautifulSoup(html.text, 'html.parser')
print(soup.find_all('li', class_='DuHQbc')) # []
print(soup.find_all('a', class_='PJLMUc')) # []
print(soup.find_all('a', class_='e0WtYb HpzMff PJLMUc')) # []
print(soup.select_one('#tab_time > div > div:nth-child(2) > div > ul > li:nth-child(2) > a')) # …Run Code Online (Sandbox Code Playgroud) 我想用动态键提取嵌套的 JSON。我目前可以借助和提取密钥,但解析 JSON 对象的值会产生意外的结果。“[对象对象]”12
使用动态键和值解析嵌套 JSON 的正确方法是什么?(我不想使用自定义 JS UDF,但我不确定现有的 JSON 函数是否可以处理该问题。)
{
"key1":{"ItemID":1,"UseCount":4,"ItemCount":7},
"key2":{"ItemID":2,"UseCount":5,"ItemCount":8},
"key3":{"ItemID":3,"UseCount":6,"ItemCount":9}
...
}
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bigquery-utils:
json_extract_keys()
json_extract_values()
WITH
sample_logs AS (
SELECT '{"key1":{"ItemID":1,"UseCount":4,"ItemCount":7},"key2":{"ItemID":2,"UseCount":5,"ItemCount":8},"key3":{"ItemID":3,"UseCount":6,"ItemCount":9}}' as json_string,
UNION ALL SELECT '{"key4":{"ItemID":1,"UseCount":4,"ItemCount":7},"key5":{"ItemID":2,"UseCount":5,"ItemCount":8}}'
)
SELECT
json_string,
key,
TO_JSON_STRING(value) as value,
FROM sample_logs
CROSS JOIN UNNEST(bqutil.fn.json_extract_keys(json_string)) as key WITH OFFSET
INNER JOIN UNNEST(bqutil.fn.json_extract_values(json_string)) as value WITH OFFSET USING (OFFSET)
;
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JSON_STRING1 | "key1" | {"ItemID":1,"UseCount":4,"ItemCount":7} -- <- not [object Object]
JSON_STRING1 | …Run Code Online (Sandbox Code Playgroud) 我想知道Python中以下变量的正确命名约定,我找不到Google Style Guide和PEP8中的一个
(假设我有以下Python代码)
output_file = open(output_file_path,'w')
out文件名的最佳变量名是什么?
我相信变量名称的可能选项就像
output_file outputfile outfile out_file outfile
和路径变量可以是这样的
output_file_path output_filepath output_path out_path ...