小编BA1*_*995的帖子

当用户在Ionic 2上滚动时,提起我很困惑.我基本上想说,当用户向下滚动页面时,做一些事情.

任何例子都会很棒.

更新:

我在我的构造函数中有这个,所以当页面滚动时我想关闭键盘,因为它被打开而没有别的方法可以关闭.

import { Component, ViewChild } from '@angular/core';
import { NavController, NavParams, Content } from 'ionic-angular';
import { Keyboard } from '@ionic-native/keyboard';

export class SearchPage {

  @ViewChild(Content)
  content:Content;

  constructor(public keyboard: Keyboard, public formBuilder: FormBuilder, public navCtrl: NavController, public navParams: NavParams, public apiAuthentication: ApiAuthentication, private http: Http) {

    this.content.ionScroll.subscribe((data)=>{
      this.keyboard.close();
    });
  }
}

但是我Cannot read property 'ionScroll' of undefined把它放在错误的地方我得到这个错误？

我的目标是

1. 创建一个从API中提取食谱的购物清单.
2. 将成分从一页送到另一页.
3. 添加多于1时刷新/加载数据的页面.

我遇到的问题是

1. 只有一套配料加载
2. 清除功能将不再允许添加.

食谱

// Loading Recipes 
/////////////////////////////////////////////////////////////////////

loadDetails1(id){
    this.apiAuthentication.loadDetails(id)
    .then(data => {
        this.api = data;
    });
}

// Add to Shopping List 
///////////////////////////////////////////////////////////////////// 

submit(api) {

    let toast = this.toastCtrl.create({
      message: 'Added to shopping list',
      duration: 1000
    });

    console.log(this.api);

    this.storage.get('myData').then((api) => {

        // add one igredient to the ingredientLines object
        // if it's still a string use JSON.parse() on it
        this.storage.set('myData', api).then(result =>{
            toast.present();
            console.log(api);
        }); 
    }); 
}

HTML

<h1 (click)="submit(api?.ingredientLines)">Add to shopping list</h1> 
<ul>
    <li …