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如何在Linux 32位计算机上解决REG_EIP未声明(在此函数中首次使用)错误?

我在使用gcc编写用C语言编写的信号处理程序时遇到错误,在出现Segmentation fault之后显示转储的寄存器值.当我尝试使用代码访问它时:

void print_registers(FILE *fd, ucontext_t *ctx, bool fpu = false)
{
        const char *flags_str[] = {
                "CF", 0, "PF", 0, "AF", 0, "ZF", "SF", "TP", "IF", "DF",
                "OF", 0, 0, "NT", 0, "RF", "VM", "AC", "VIF", "VIP", "ID"
        };

        greg_t *regs = ctx->uc_mcontext.gregs;

        void *eip[1] = { (void*)regs[REG_EIP] };

        char **symbol = backtrace_symbols(eip, 1);

        fprintf(fd, "Registers:\neip is at ");

         backtrace_symbols_fd(eip, 1, fd->_fileno);

        size_type flags = regs[REG_EFL];
        fprintf(fd, "eflags: %x [ ", flags);
        for (size_type i = 0; i < …
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c linux gcc signal-handling

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