小编Dom*_*ikM的帖子

我在SO上找到了关于这个问题的几个问题和答案,但它们似乎都涵盖了问题的一个主要原因:在事务之外或在另一个事务中获取集合.但在我的情况下,我在获取父对象和集合时在同一事务中获取.

@Service
@Transactional
public class IntegrationServiceImpl implements IntegrationService {
@Override
    public Integration getIntegrationByIdFetchBackendParameters(Long integrationId) {
        Integration integration = integrationDao.get(integrationId);
        //not all integrations have to have backend.
        if (integration.getBackend() != null) {
            Hibernate.initialize(integration.getBackend().getBackendParameters());
        }
        return integration;
    }
...

但是当谈到Hibernate.initialize这个分支在org.hibernate.collection.internal.AbstractPersistentCollection中执行

if ( session == null ) {
                throw new HibernateException( "collection is not associated with any session" );
            }

我不能明白为什么session是null.有人会解释这个并提出解决方案吗？

编辑1 - 完整堆栈跟踪

org.hibernate.HibernateException: collection is not associated with any session
        at org.hibernate.collection.internal.AbstractPersistentCollection.forceInitialization(AbstractPersistentCollection.java:676)
        at org.hibernate.Hibernate.initialize(Hibernate.java:77)
        at com.dhl.finFw.service.IntegrationServiceImpl.getIntegrationByIdFetchBackendParameters(IntegrationServiceImpl.java:169)
        at …

我有一个带消息的属性文件,我想处理一些复数的特殊情况.现在我使用:

xxx.yyy.plural=test{0,choice,2#y}

但它也将12格式化为"暴躁".如何指定2为完全匹配？

我正在用H2数据库编写集成测试.我的数据库(生成)初始化包含此脚本(因为生成的连接表没有此列):

ALTER TABLE INT_USR ADD IU_INSDTTM TIMESTAMP DEFAULT NOW();

这是我创建记录的方式:

Integration integrationOne = createIntegration(firstId, "FIRST");
Integration integrationTwo = createIntegration(secondId, "SECOND");
flushAndClear();
userService.logRecentIntegration(integrationOne.getId(), user.getId());
flushAndClear();
userService.logRecentIntegration(integrationTwo.getId(), user.getId()); //1

方法logRecentIntegrations(..,..)只调用DAO,dao执行此操作:

Query query = entityManager.createNativeQuery(
    "INSERT INTO INT_USR (USR_ID, INT_ID) VALUES (?, ?)");
query.setParameter(1, userId)
    .setParameter(2, integrationId);
query.executeUpdate();

后来在我的测试中:

Query query = entityManager.createNativeQuery(
    "SELECT * FROM INT_USR ORDER BY IU_INSDTTM");
List resultList = query.getResultList();

当我在resultList中调试此测试时,有两个记录(正确)但它们具有相同的时间戳.即使我在标记为// 1的行上插入断点并等待一段时间 - 因此插入之间的时间间隔也很重要.(Thread.sleep - 相同的结果)

我试图将SQL脚本修改为

ALTER TABLE INT_USR ADD IU_INSDTTM TIMESTAMP DEFAULT CURRENT_TIMESTAMP;

但结果相同.为什么两个结果都有相同的时间戳？

我和CustomerUnit之间有很多关系:

public class Customer extends AbstractEntity {

    @JoinTable(name = "CUS_BUS_UNITS", 
            joinColumns = {
                @JoinColumn(name = "CUS_ID", referencedColumnName = "CUS_ID")},
            inverseJoinColumns = {
                @JoinColumn(name = "BUS_ID", referencedColumnName = "BUS_ID")})
    @ManyToMany
    private Collection<BusinessUnit> businessUnits;
}

public class BusinessUnit extends AbstractEntity {

    @ManyToMany(mappedBy = "businessUnits")
    private Collection<Customer> customers;

}

当我调用entityManager.merge(customer)时; 在客户(已经在DB中,没有改变)我在日志中看到这两个sql命令:

Hibernate:更新CUSTOMERS设置CUS_DESCR =？,CUS_NAME =？,CUS_ENABLED =？哪里有CUS_ID =？Hibernate:从CUS_BUS_UNITS中删除CUS_ID =？

为什么hibernate试图从连接表中删除记录？我只需要在连接表中更新客户记录和可能的记录 - 取决于我是否在客户上添加或删除了业务单位.不应更新,删除或插入业务单位.

编辑: 我的equals/hashCode是(在AbstractEntity中定义):

public int hashCode() {
    if (getId() != null) {
        return getId().hashCode();
    }
    return super.hashCode();
}
public boolean equals(Object obj) {
    if …

这是我的实体:

public class Account extends AbstractEntity<Long> {

    @Id
    @SequenceGenerator(name = "accountSequence", sequenceName = "SQ_ACCOUNTS", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "accountSequence")
    @Column(name = "ACC_ID", nullable = false)
    private Long id;
...
}

public class Integration extends AbstractEntity<Long> {

    @Id
    @SequenceGenerator(name = "integrationSequence", sequenceName="SQ_INTEGRATIONS", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "integrationSequence")
    @Column(name = "INT_ID", nullable = false)
    private Long id;
...
public void addIntegration(Integration integration) {
        IntegrationAccount association = new IntegrationAccount();
            // This does not help
        //association.setIntAccountsPK(new …

我的目标是从java中的字符串中提取名称和数字.示例:输入 - >输出

1234 - >数字:[1234],姓名:[]

1234,34,234 - >数字:[1234,34,234],名称:[]

12,foo,123 - >数字:[12,123],姓名:[foo]

foo3,1234,4bar,12,12foo34 - >数字:[1234,12],姓名:[foo3,4bar,12foo34]

foo,bar - > - > numbers:[],姓名:[foo,bar]

我想出了[^,]+(,?!,+)*匹配字符串的所有部分,但我不知道如何只匹配数字或名称(名称可以包含数字 - 如例子).谢谢

我在SO上阅读了关于这个主题的所有答案(不仅仅是),但这些都没有解决我的问题.我有数据表:

<p:dataTable 
                value="#{reportBean.reportData.rows}"
                var="row" 
                styleClass="listBlock dataTableOverflowAuto fullScreenTable"
                rendered="#{!reportBean.reportData.grouped}">
                 <f:facet name="header">
                    #{msg['report.table.header']}
                </f:facet>

                <p:column>
                    #{row.integrationName}
                </p:column>

                <p:column>
                    #{row.integrationId}
                </p:column>

                <p:column>
                    #{row.service}
                </p:column>

                <p:columns value="#{reportBean.reportData.columns}"
                           var="column">  
                    <f:facet name="header">  
                        #{column}
                    </f:facet>  
                    <h:outputText value="#{row.getData(column)}" escape="false" />  
                </p:columns>

reportBean上的getReportData()非常简单(无计算):

public ReportDataInterface getReportData() {
        return reportData;
}

返回的数据是:

public class NoneGroupedReportData implements ReportDataInterface {
    private int counter = 0;
    Logger logger = LoggerFactory.getLogger(getClass());
    private List<String> columns = new LinkedList<String>();
    public void addRow(Row row) {
        addColumns(row);
    }

    public List<String> getColumns() {
        counter++;
        logger.debug("getColumns called {} times", counter); …

我有一个与此线程中描述的类似问题：Show/hide JSF2 form using selectBooleanCheckbox。但该线程中提出的解决方案对我不起作用。我想要一个可以通过选中复选框来扩展的表单。

我的设置如下：

<p:selectBooleanCheckbox id="lookupCheck" value="#{addressDetailBean.addQLookup}">
    <p:ajax event="change" update="qlookupcolumn1" process="@this"/>
</p:selectBooleanCheckbox>
<p:outputPanel id="qlookupcolumn1" rendered="#{addressDetailBean.addQLookup}">
    <h2>#{msg['qloookup.new.title']}</h2>
    <ui:include src="/WEB-INF/includes/integration/qlookupDetailColumns.xhtml">
        <ui:param name="bean" value="#{addressDetailBean}" />
    </ui:include>
</p:outputPanel>

但是当我检查复选框表单时，未呈现。Bean 被调用并且属性被正确设置，我可以在响应中看到表单，但它没有呈现在页面上。

可能出了什么问题？