我的目标是仅从字符串集中的括号中删除重复的单词.
a = c( 'I (have|has|have) certain (words|word|worded|word) certain',
'(You|You|Youre) (can|cans|can) do this (works|works|worked)',
'I (am|are|am) (sure|sure|surely) you know (what|when|what) (you|her|you) should (do|do)' )
我想要的就是这样
a
[1]'I (have|has) certain (words|word|worded) certain'
[2]'(You|Youre) (can|cans) do this (works|worked)'
[3]'I (am|are) pretty (sure|surely) you know (what|when) (you|her) should (do|)'
为了得到结果,我使用了这样的代码
a = gsub('\\|', " | ", a)
a = gsub('\\(', "( ", a)
a = gsub('\\)', " )", a)
a = vapply(strsplit(a, " "), function(x) paste(unique(x), collapse = " "), character(1L))
但是,它导致了不良产出.
a …通过R，我可以轻松地创建一个数据帧，其中包含来自字符串列表的某些字符串模式的频率。
library(stringr)
library(tm)
library(dplyr)
text = c('i am so hhappy happy now','you look ssad','sad day today','noway')
dat = sapply(c('happy', 'sad'), function(i) str_count(text, i))
dat = data.frame(dat)
dat = dat %>% mutate(Sentiment = (happy)-(sad))
结果，我可以有一个这样的数据框
happy sad Sentiment
1 2 0 2
2 0 1 -1
3 0 1 -1
4 0 0 0
在Python中，我可以假设其余代码 sapply()
import pandas as pd
text = ['i am so hhappy happy now','you look ssad','sad day today','noway']
????
dat = pd.DataFrame(dat)
dat['Sentiment'] …