我在网站上有一个登录页面.我有4个不同的用户,我希望当他们登录时,他们会根据他们分配的角色转到不同的页面.
有什么办法吗?
当我尝试在我buildForm的一个表单中传递一个选项到我的方法时,我收到以下错误.
选项"numOfHoles"不存在.定义的选项包括:"action","allow_extra_fields","attr","auto_initialize","block_name","by_reference","cascade_validation","compound","constraints","csrf_field_name","csrf_message","csrf_protection ","csrf_provider","csrf_token_id","csrf_token_manager","data","data_class","disabled","empty_data","error_bubbling","error_mapping","extra_fields_message","inherit_data","意图", "invalid_message","invalid_message_parameters","label","label_attr","label_format","mapped","max_length","method","pattern","post_max_size_message","property_path","read_only","required" ","translation_domain","trim","validation_groups","虚拟".
在我的控制器中:
// hardcoded here for brevity in this example
$form = $this->createForm('crmpicco_course_row', $courseRow, array('numOfHoles' => 18));
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在crmpicco_course_rowForm类中:
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('name', 'text')
->add('course', 'crmpicco_course', array('numOfHoles' => $options['numOfHoles']))
;
}
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在crmpicco_courseForm类中:
public function buildForm(FormBuilderInterface $builder, array $options)
{
for ($i = 0; $i < $options['numOfHoles']; $i++) {
$builder->add($i, 'text', array('required' => 'false'));
}
}
/**
* @return string name
*/
public function getName()
{ …Run Code Online (Sandbox Code Playgroud) $custom = Array(
Array(
'name' => $name1,
'url' => $url1
),
Array(
'name' => $name_a,
'url' => $url_a
)
);
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我试图用以下内容拼接数组:
$bread_elem = array('name' => 'Golf', 'url' => $slug . $parent_slug);
array_splice($custom, 1, 0, $bread_elem);
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我希望我的数组成为以下数组,其值$sale_bread_elem插入数组中的第一位.我看不出我做错了什么.
$custom = Array(
Array(
'name' => $name1,
'url' => $url1
),
Array(
'name' => 'Golf',
'url' => $slug . $parent_slug
),
Array(
'name' => $name_a,
'url' => $url_a
)
);
Run Code Online (Sandbox Code Playgroud) 在Smarty你可以做到
{$var = 'bla' scope=parent}
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在Twig有可能吗?
不建议使用块.我知道.我需要变量.
我知道PhpStorm可以连接到数据库并使用它.是否可以使用phpstorm将数据库导出到myDb.sql文件?
每当我使用显然使用 Python 的 AWS CLI 时,我都会收到以下错误。
aws --version
WARNING: Executing a script that is loading libcrypto in an unsafe way. This will fail in a future version of macOS. Set the LIBRESSL_REDIRECT_STUB_ABORT=1 in the environment to force this into an error.
aws-cli/1.16.15 Python/2.7.16 Darwin/19.0.0 botocore/1.12.5
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我在 macOS 10.15.1 (19B88) 上运行它,内核版本:Darwin 19.0.0。
我的应用程序在 Python 2 上运行(目前),所以我还不能升级 Python。
这是由运行即将不受支持的 Python 版本引起的吗?
我在我的Google Analytics跟踪代码中设置了自定义维度,但是我在Chrome控制台中看到了一个奇怪的错误,其中启用了Google Analytics调试程序.
这是我在每个页面上触发的代码.我正在向区域帐户以及全局/汇总帐户报告,我创建了两个跟踪器来实现此目的.
<script>
(function(i,s,o,g,r,a,m){i['GoogleAnalyticsObject']=r;i[r]=i[r]||function(){
(i[r].q=i[r].q||[]).push(arguments)},i[r].l=1*new Date();a=s.createElement(o),
m=s.getElementsByTagName(o)[0];a.async=1;a.src=g;m.parentNode.insertBefore(a,m)
})(window,document,'script','https://www.google-analytics.com/analytics.js','ga');
ga('create', 'UA-85521872-1', 'auto', 'crmpiccoglobal');
ga('create', 'UA-85521872-3', 'auto', 'crmpiccoregion');
ga('set', 'dimension1', 'premium');
ga('crmpiccoglobal.send', 'pageview');
ga('crmpiccoregion.send', 'pageview');
</script>
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在控制台中我看到了这个:
运行命令:ga("set","dimension1","premium")
analytics_debug.js:10命令被忽略.未知目标:未定义
我已经在GA中创建了自定义维度,我想在其中访问它.
有没有办法减少Glyphicons的"重量"?
我正在使用" ok "Glyphicon <span class="glyphicon glyphicon-ok"></span>,显示如下:
有没有办法减少重量,以产生更薄的刻度而不减小字体大小?改变font-weight为lighter没有任何影响.
当我运行时,bin/console doctrine:migrations:list我看到迁移列出为:
Application\Migrations\Version20210909072642
我正在尝试回滚迁移,并且尝试了几个不同的版本:
bin/console --env=dev doctrine:migrations:execute 'Application\DoctrineMigrations\Version20210909072642' --down --no-interaction -vvv
bin/console --env=dev doctrine:migrations:execute Version20210909072642 --down --no-interaction -vvv
bin/console --env=dev doctrine:migrations:execute 20210909072642 --down --no-interaction -vvv
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最近的DoctrineMigrationsBundle更新是否改变了此功能?
每次我运行它时都会出现以下错误:
In MigrationClassNotFound.php line 15:
[Doctrine\Migrations\Exception\MigrationClassNotFound]
Migration class "20210909072642" was not found?
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我的 Doctrine 配置如下所示:
doctrine_migrations:
migrations_paths:
'Application\Migrations': 'app/DoctrineMigrations'
storage:
table_storage:
table_name: 'migration_versions'
Run Code Online (Sandbox Code Playgroud) 使用jQuery:使用以下代码我想阻止href url(在这种情况下是一个哈希'#')在点击时被触发,但仍然允许click事件继续冒泡链.怎么能实现呢?
<div>
<a href="#">Test</a>
</div>
$('a').click(function(e){
// stop a.click firing but allow click event to continue bubbling?
});
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symfony ×3
array-splice ×1
click ×1
css ×1
database ×1
doctrine ×1
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events ×1
fonts ×1
forms ×1
glyphicons ×1
html ×1
javascript ×1
jquery ×1
libcrypto ×1
macos ×1
mysql ×1
mysqldump ×1
openssl ×1
php-5.6 ×1
phpstorm ×1
python ×1
python-2.7 ×1
scope ×1
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