小编Moh*_*med的帖子

我知道如果User.json文件有

{
  "name" : { "first" : "Joe", "last" : "Sixpack" },
  "gender" : "MALE",
  "verified" : false,
  "userImage" : "Rm9vYmFyIQ=="
}

我可以像这样构造一个User对象:

User user = mapper.readValue(new File("user.json"), User.class);

但是如果文件User.json具有以下内容,我该如何构造对象列表:

{
  "name" : { "first" : "Joe", "last" : "Sixpack" },
  "gender" : "MALE",
  "verified" : false,
  "userImage" : "Rm9vYmFyIQ=="
},
{
  "name" : { "first" : "Jane", "last" : "Austen" },
  "gender" : "FEMALE",
  "verified" : false,
  "userImage" : "DFREWEWE=="
}

？

我有一个层次结构,其中Square,Triangle和Circle都从Shape扩展.我有一个工作方法:

public void someMethod() {
   File file = new File("File_with_squares");
   ThirdPartyClass foo = new ThirdPartyClass();
   Square[] squares = foo.someMajicMethod(Square[].class,file);
   for (Square square: squares) 
      square.draw();

}

现在我想使这个方法通用,以便它可以接受任何形状.我想能够打电话someMethod(Triangle.class,new File("File_with_triangles")或someMethod(Circle.class, new File("File_with_circles").我这样想:

public void someMethod(Class<? extends Shape> type, File shapeFile) {
   ThirdPartyClass foo = new ThirdPartyClass();
   #### What goes here??? ####
   for (Shape shape: shapes)
       shape.draw();
}

应该在####那里有什么？#### ???