我在解决方案附近吗?我总是得到双倍数量的辅音.
我确信这是正确的做法.
function consonants(str) {
var countConsonants = 0;
for (var i = 0; i <= str.length; i++) {
if (str[i] !== "a" || str[i] !== "e" || str[i] !== "i" ||
str[i] !== "o" || str[i] !== "u" || str[i] !== " ") {
countConsonants += 1;
}
}
return (countConsonants);
}
consonants("asdfghaaa");Run Code Online (Sandbox Code Playgroud)
我期待5的答案,即sdfgh辅音.
javascript ×1