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如何从HttpServletRequest(Tomcat 9.0)获取查询参数?

服务器接收来自两个客户端的请求 - Raspberry Pi和Android应用程序,两者都使用HttpURLConnection发送请求.我需要通过theese请求传递参数,例如:

http://192.168.0.10:8080/MyProject/MyServer/rpi/checktask?rpi="rpi"
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这样做:

String requestUrl = "http://192.168.0.10:8080/MyProject/MyServer/rpi";
String query = String.format("/checktask?rpi=%s",
                        URLEncoder.encode("rpi", "UTF-8"));
URL url = new URL(requestUrl + query);
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.setRequestProperty("Accept-Charset", "UTF-8");
conn.connect();
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Servlet有注释:

@WebServlet(name = "MyServer", urlPatterns = { "/MyServer/rpi/*", "/MyServer/app/*"})
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但是当Servlet获得上述请求时,会发生以下情况:

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

String path = request.getRequestURI();     // /MyProject/MyServer/rpi/*
String query = request.getQueryString();   // null
String context = request.getContextPath(); // /MyProject
String servlet = request.getServletPath(); // /MyServer/rpi
String info = request.getPathInfo(); …
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java tomcat servlets

9
推荐指数
1
解决办法
3万
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