小编im *_*ess的帖子

我正试图操纵一个字符串..

例如:

string DiagnosesString  "250.00 03 350.0001 450.00 01 550.00 02";

产量

250.00
350.00
450.00
550.00

我试图使用Split方法.正如您在350.0001中的示例中所看到的,其输出为350.00.

我可以删除03,02等.

问题:1.)我将如何删除350.0001的o1只获得350.00？

这是我的代码:

string DiagnosisCodestemp = DiagnosesString.Replace(" 01 ", " ").Replace(" 02 ", " ").Replace(" 03 ", " ").Replace(" 04 ", " ").Replace(" 05 ", " ").Replace(" 06 ", " ").Replace(" 07 ", " ");
string[] DiagnosisCodesParts = DiagnosisCodestemp.Split();

我不知道在列表视图或转发器中放入删除线.我只想在描述中留下删除线.

这里我的asp代码:

  <div class="price" CssClass="Sline"><%#RenderPrice2((decimal)Eval("lb_sellingprice"))%></div>

谢谢!

通过javascript启用和禁用复选框,例如当我检查chk1然后chk2,chk3和chk4将启用,如果我取消选中chk1然后chk2,chk3和chk4将通过javascript禁用？

这是我的代码:

<script type="text/javascript">
$('chkTAR').clicked(function(){
        {
        if($('chkTAR :checked').length == 2)

        $('chkOasis, chkPOT').disabled = true;
        else
        $('chkOasis, chkPOT').disabled = false
        });
</script>

我无法使用此代码插入值:

 insert into t_category_values (CategoryCode,
 CategoryValueCode, CategoryValue) values(2, 1, 1);

错误消息

no primary key

我试图在下拉菜单列表中显示文档的id和descritption但我不知道该怎么做.到目前为止它工作正常,但只显示参考文件.

<asp:DropDownList ID="TrainingDocIDTextBox" runat="server"
DataSourceID="AccessDataSource2" DataTextField="ReferenceDocument"
DataValueField="TrainingDocID"
onselectedindexchanged="TrainingDocIDTextBox_SelectedIndexChanged">
</asp:DropDownList>

谢谢!

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
Create PROCEDURE [dbo].[SD_Sproc_Insurance_Insert] 
    -- Add the parameters for the stored procedure here
(
    @HCSInsuranceID bigint,
    @HCSInsuranceCode varchar(10),
    @HCSInsuranceName varchar(100),
    @IsPPS bit,
    @IsActive bit
)
AS
BEGIN TRAN InsuranceInsert
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    INSERT INTO SD_Sproc_ToGRS_Insurance(HCSInsuranceID ,HCSInsuranceCode, HCSInsuranceName, IsPPS ,IsActive)
            VALUES (@HCSInsuranceID ,@HCSInsuranceCode, @HCSInsuranceName, @IsPPS, @IsActive);

COMMIT TRAN InsuranceInsert

该SD_Sproc_ToGRS_Insurance是存储在我会打电话给..我有一个问题,调用此一个.有谁建议？我正在做一个调用存储过程的正确途径？

我已经dropdownlist在转发器上检索了我的数据库(DescriptionCode).

现在,我正在尝试在我的数据库中保存/添加/插入下拉列表的选定值但是我

失败.

感激地收到任何帮助.谢谢!

 protected void GeneralRepeater_OnItemDataBound(object sender,
                                               RepeaterItemEventArgs e)
    {
        if (e.Item.ItemType == ListItemType.Item ||
            e.Item.ItemType == ListItemType.AlternatingItem)
        {
            DropDownList myDDL = (DropDownList)e.Item.FindControl("GeneralDDL");
            Diagnosis oDiagnosis = new Diagnosis();
            PlanOfCare oPlanOfCare = new PlanOfCare();
            DataView dv = new DataView(oDiagnosis.GetDiagnosis());
            myDDL.DataSource = PatientDiagnosis1;
            myDDL.DataTextField = "DiagnosisCode";
            myDDL.DataValueField = "DiagnosisCode";
            myDDL.DataBind();

            //PUT AN EMPTY FIELD FOR DROPDOWNLIST
            ListItem LI = new ListItem("", "");
            myDDL.Items.Insert(0, LI);
            myDDL.SelectedValue = "0";



        }
    }


 protected void cmdSave_Click(object sender, EventArgs e)
    {
    oPlanofCareSave.DiagnosesCode = //[1]this …

这是我继续工作:在C#中添加DateTime 我已经可以在我的日期添加日期.

我的问题是:

a.)可以将一年乘以日期时间吗？例如.

DateTime newDate = DateTime.Today.AddDays(10);
long xDate = DateTime.Now.Year * newDate; // error : Operator '*' 
           // cannot be applied to operands of type 'int' and 'System.DateTime

我已经完成了关于加密的程序.问题是,我需要一个捷径.我编写的程序太长而且不太合适.我刚接触c ++编程.有人可以帮我吗？谢谢!:)这是我的程序:

#include <iostream.h>
#include <stdlib.h>
#include <stdio.h>
#include <conio.h>
int main()
{
c:char crypt[25], cons; 
int ctr;
cout<<"Input your 26-character cipherstring below.\n\n";
cout<<"ABCDEFGHIJKLMNOPQRSTUVWXYZ\n";cin>>crypt;
e:char string[65535];
cout<<"\nInput your string (input your spaces as any non-alphabet character).\n";cin>>string;
cout<<"\n\nEncrypted string: "; //std::string 
for(ctr=0;ctr<=strlen(string);ctr++)
{
switch(string[ctr])
{
case('a'): cout<<crypt[0]; break;
case('b'): cout<<crypt[1]; break;
case('c'): cout<<crypt[2]; break;
case('d'): cout<<crypt[3]; break;
case('e'): cout<<crypt[4]; break;
case('f'): cout<<crypt[5]; break;
case('g'): cout<<crypt[6]; break;
case('h'): cout<<crypt[7]; break;
case('i'): cout<<crypt[8]; break;
case('j'): cout<<crypt[9]; break;
case('k'): cout<<crypt[10]; break;
case('l'): cout<<crypt[11]; break; …