这看起来很简单,但我从jqGrid代码中得到这个神秘的错误,说"元素不是表".这是代码:
var grid_data = [ {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"1",invdate:"2010-05-24",name:"test",note:"note",tax:"10.00",total:"2111.00"} , {id:"2",invdate:"2010-05-25",name:"test2",note:"note2",tax:"20.00",total:"320.00"}, {id:"3",invdate:"2007-09-01",name:"test3",note:"note3",tax:"30.00",total:"430.00"}, {id:"4",invdate:"2007-10-04",name:"test",note:"note",tax:"10.00",total:"210.00"}, {id:"5",invdate:"2007-10-05",name:"test2",note:"note2",tax:"20.00",total:"320.00"}, {id:"6",invdate:"2007-09-06",name:"test3",note:"note3",tax:"30.00",total:"430.00"}, {id:"7",invdate:"2007-10-04",name:"test",note:"note",tax:"10.00",total:"210.00"}, {id:"8",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"21.00",total:"320.00"}, {id:"9",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"11",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"12",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"13",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"14",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"15",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"16",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"17",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"18",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"19",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"21",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"22",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"23",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"24",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"25",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"26",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"}, {id:"27",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"28",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}, {id:"29",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"} ];
var default_grid = {
datatype: "local",
height: 80,
rowNum: 10,
rowList: [10,20,30],
multiselect: true,
rowList:[10,20,30],
sortname: 'id', viewrecords: true, sortorder: "asc",
footerrow: true,
loadui: "block"
};
var grid_detail = $.extend({
data: grid_data,
colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
colModel:[
{name:'id',index:'id', width:60, sorttype:"int"}, {name:'invdate',index:'invdate', width:90, sorttype:"date", formatter:"date"},
{name:'name',index:'name', …CSS:
ul {
float: left;
margin-right:20px;
}
ul li {
height: 3em;
border: 1px solid #ff0000;
width:200px;
}
HTML:
<ul>
<li> Some text</li>
<li>Some text<br />some more text</li>
<li>some test text3</li>
<li>even more text<br />and more</li>
</ul>
<ul>
<li> Some text</li>
<li>Some text<br />some more text</li>
<li>some test text</li>
<li>even more text<br />and more</li>
</ul>
这是微不足道的,垂直对齐文本并使高度等于行高,如果你只有一行,但不止于此,事情看起来非常棘手.
有人知道转这个的好方法吗？:
var obj = [{key1: value1,key2: value2},{key3: value3,key4: value4}];
成:
var obj = [{Key1: value1,Key2: value2},{Key3: value3,Key4: value4}];
这就是我想要的:
attribute_name attribute_id attribute_value
--------------------------------------------------------------------
Appliances 16, 17, 18, 19 Washer, Dryer, Dishwasher, Microwave
Consoles 7, 3 PS3, XBox
这里接近我所拥有的:
attribute_name attribute_id attribute_value
-------------------------------------------------
Appliances 16 Washer
Appliances 17 Dryer
Appliances 18 Dishwasher
Appliances 19 Microwave
Consoles 7 PS3
Consoles 3 XBox
...来自此查询:
SELECT a.name AS attribute_name,
av.attribute_value_id, av.value AS attribute_value
FROM attribute_value av
INNER JOIN attribute a
ON av.attribute_id = a.attribute_id
WHERE av.attribute_value_id IN
(SELECT attribute_value_id
FROM property_attribute
WHERE property_id = 1)
ORDER BY a.name;
我没有成功使用GROUP_CONCAT.我甚至不知道我想要什么是可能的.
在 sequelize.js 中尝试以下原始 MySQL 插入时：
mysql_sequelize.query( 'INSERT IGNORE INTO steamer(steamer_id, prov_id, name, avatar) VALUES(UNHEX(REPLACE(UUID(),\'-\',\'\')), \'' + prov_id + '\', \'' + steamer_name + '\', \'' + steamer_avatar + '\')')
.then(function (data) {
console.log('inserted STEAMER data---> ',data); // no useful info
});
);
生成的控制台日志如下所示：
inserted STEAMER data---> [ OkPacket {
fieldCount: 0,
affectedRows: 1,
insertId: 0,
serverStatus: 2,
warningCount: 1,
message: '',
protocol41: true,
changedRows: 0 },
OkPacket {
fieldCount: 0,
affectedRows: 1,
insertId: 0,
serverStatus: 2,
warningCount: 1,
message: '', …我知道这个标题听起来很荒谬,但我已经做了几个小时的研究,现在却发现PDO最终没有明显的解决方案......我致力于为一个开放.我也愿意接受我的代码存在缺陷.
使用PHP 5.2/Ubuntu,此代码可以工作(不使用预处理语句/打开注入):
$sql ="SELECT COUNT(*) FROM property p
INNER JOIN property_attribute pa ON p.property_id = pa.property_id
INNER JOIN property_area pc ON p.property_id = pc.property_id
WHERE pa.attribute_value_id
IN (
SELECT av.attribute_value_id
FROM attribute_value av
INNER JOIN attribute a ON av.attribute_id = a.attribute_id
WHERE a.name LIKE '$attributes'
AND av.value LIKE '$values'
)
ORDER BY p.price ASC";
$params = array();
$rHowManyPages = Listings::HowManyPages($sql, $params);
但是,使用PDO精心准备的声明:
$sql ='SELECT COUNT(*) FROM property p
INNER JOIN property_attribute pa ON p.property_id = pa.property_id
INNER JOIN property_area …我正在尝试编写一个立即执行的函数,但也可以在以后执行:
var test = function (e){ console.log('hello'+e); }();
$('#some_element').click(function(e){
test(' world');
});
在这种情况下,我想要的结果是:
helloundefined hello world
我没有理解为什么调用测试后来返回'测试不是一个函数'.
每次我用新的菜单项更新数据库时，我都会尝试让路由再更新一条路由。这是我悲伤的、丑陋的小尝试：
在 app.js 中，我检查菜单数据库和 shazaam...路线是在启动时动态创建的。凉爽的！：
// in app.js //
var attachDB = function(req, res, next) {
req.contentdb = db.content;
req.menudb = db.menu;
req.app = app; // this is the express() app itself
req.page = PageController;
next();
};
db.menu.find({}, function (err, menuitems){
for(var i=0; record = menuitems[i]; i++) {
var menuitem = record.menuitem;
app.all('/' + menuitem, attachDB, function(req, res, next) {
console.log('req from app all route: ',req)
PageController.run(menuitem, req, res, next);
});
}
http.createServer(app).listen(config.port, function() {
console.log(
'\nExpress server listening …我有一个按钮用于在选中时删除一行调用内置函数'delRowData'.很简单,直到你想删除一行/多行(如内置变量'selarrrow').有没有人比我想出的可怕的渣土有更好的答案(例如修改核心jqGrid代码)？
这是我的代码:
$("#deleteButton").click(function(){
var gr = jQuery("#myGrid").jqGrid('getGridParam','selarrrow');
var su=jQuery("#myGrid").jqGrid('delRowData',gr.toString());
(su) ? '' : alert("Already deleted or not in list");
});
现在是在jquery.jqGrid.min.js中修改核心代码的非常讨厌的部分:
delRowData:function(f){
for(var m=0,max=f.length;m<max;m++){
var j=false,i,c;
this.each(function(){
var e=this;
if(i=e.rows.namedItem(f[m])){
b(i).remove();
e.p.records--;
e.p.reccount--;
e.updatepager(true,false);
j=true;
if(e.p.multiselect){
c=b.inArray(f[m],e.p.selarrrow);
c!=-1&&e.p.selarrrow.splice(c,1)
}
if(f==e.p.selrow)e.p.selrow=null
}else return false;
if(e.p.datatype=="local"){
var k=e.p._index[f[m]];
if(typeof k!="undefined"){
e.p.data.splice(k,1);
e.refreshIndex()
}
}
});
}
/*if(e.p.altRows===true&&j){
var n=e.p.altclass;b(e.rows).each(function(a){
a%2==1?b(this).addClass(n):b(this).removeClass(n)
})
}*/
return j
}
有一个更好的方法吗？
/ *新细节**/
所以即使我们迭代给定的jqGrid数组'selarrrow'并使用jqGrid的默认'delRowData'函数逐个删除行:
$("#deleteButton").click(function(){
$.each($("#myGrid").jqGrid('getGridParam','selarrrow'), function(index, value) {
console.log($("#myGrid").jqGrid('getGridParam','selarrrow'));
if ($("#myGrid").jqGrid('delRowData', value)) {
console.log($("#myGrid").jqGrid('getGridParam','selarrrow'));
console.log(value); …