小编Kri*_*ian的帖子

我很难过.我正在做一个简单的ajax表单,用户将输入数据并将数据发送到服务器.

我有以下代码:

<?php
require("/mnt/library/configdb.php");        
require("/mnt/library/accessdb.php");

db_config_utility();
db_connect();

//Assign passed parameters
$submitDate = $_POST['submitDate'];
$mname      = $_POST['mname'];
$mid        = $_POST['mid'];
$coffice    = $_POST['coffice'];
$street     = $_POST['street'];
$city       = $_POST['city'];
$state      = $_POST['state'];
$zipcode    = $_POST['zipcode'];
$lat        = $_POST['lat'];
$lng        = $_POST['lng'];

//Setting up sql call
$sql="INSERT INTO manholes(
    submit_date,
    manhole_name, 
    manhole_id, 
    central_office, 
    street,
    city,
    state,
    zipcode,
    latitude,
    longitude
    )
    VALUES (
    '$submitDate',
    '$mname',
    '$mid',
    '$coffice',
    '$street',
    '$city',
    '$state',
    '$zipcode',
    '$lat',
    '$lng'
    )";

    echo("SQL: " . $sql);

//Making sql calls
mysql_query($sql);
?> …

我正在使用指令来尝试替换一些经常重复发生的模板代码,我必须用更简单的东西来编写代码.

假设我有以下原始标记:

<!-- section with repeating stuff in it -->
<div some-attributes etc="etc" very-long-tag="true">
    <p class="lead">Some description text</p>

    <div class="row section short" ng-repeat="row in things">
      <div class="col-sm-6 col-md-4" ng-repeat="app in row.col">
        <div class="thumbnail">
          <img ng-src="im/things/{{app.image}}" alt="..." class="img-circle" width="250">
          <div class="caption">
            <h3>{{app.name}}</h3>
            <p>{{app.desc}}</p>
          </div>
        </div>
      </div>
    </div>
</div>

我希望通过这样做来简化它:

<!-- section with repeating stuff in it -->
<xx title="Some description text">
    <!-- this innerHTML gets passed to the directive -->
    <div class="row section short" ng-repeat="row in things">
      <div class="col-sm-6 col-md-4" ng-repeat="app …

在PHP中,我有以下字符串: =CA=CC=D1=C8=C9

什么是字符编码？

如果我有以下字符串:"brasil"和"brasil-carinhoso",我只想替换"brasil",但如果它直接跟随其他字符则不能.

所以,如果我有这个列表:"pac pac pac brasil brasil-carinhoso pac brasil",如果我尝试使用以下代码,它会失败:

//$_GET['exclusion_tags'] is 'brazil'
//$tags_maior is the string: "pac pac pac brasil brasil-carinhoso pac brasil" 
$tags_maior = preg_replace('/\b'.$_GET['exclusion_tags'].'\b/u', "", $tags_maior);

当我像这样使用str_replace或preg_replace时,我得到"pac pac pac -carinhoso pac",我需要得到"pac pac pac brasil-carinhoso pac"

我究竟做错了什么？