我在安装Anaconda之前安装了Spyder IDE(在Ubuntu 14.04上),当我键入终端时,python我有anaconda python,我可以导入它的所有软件包.但是在Spyder上我仍然有原始的python,我无法导入Anaconda软件包,我怎样才能设置Spyder使用Anaconda python?
所以我有一长串条件应该被证实是真的.if我没有把长条件链接起来,而是试图"创新"并且这样做,我认为这更具可读性.但我的问题是,这是最佳的做法吗?
或者有一种pythonic方式吗?PS:请回答替代方案,而不是回答"否",谢谢!
这是代码块:
def site_exists(site):
"""
returns the sitebean if it exists,
else returns false
"""
vpadmin_service = _get_vpadmin_service(site)
all_sites = VpAdminServiceUtil.getSites(vpadmin_service)
for site_listing in all_sites:
if site.getId():
#condition check
try:
assert site.getId() == site_listing.getId()
assert site.getName() == site_listing.getName()
assert site.getCustomer().getId() == site_listing.getCustomer().getId()
except AssertionError:
continue
#pass conditions
return site_listing
#no id, so just check for name and customer
else:
#condition check
try:
assert site.getName() == site_listing.getName()
assert site.getCustomer().getId() == site_listing.getCustomer().getId()
except AssertionError:
continue
#pass conditions
site.setId(site_listing.getId())
return …Run Code Online (Sandbox Code Playgroud) 我正在尝试编写一个小的"透视"javascript应用程序,它允许我通过一组居住在3d空间中的x,y,z点.
我有一个相机的概念,它改变了它的旋转和xyz位置,而每个点保持一个恒定的xyz点.
然后,我有一组方程式,计算出如何调整相机的x,y,z坐标以便直接向前飞行.x,y,z调节显然取决于相机的旋转.
它几乎可以工作,但在某些"态度"下,摄像机位置调整出错并且飞行路径不会直线前进,而是以某个角度熄灭,甚至是反转.计算投影的公式如下:
var directionFactor = 1;
if (direction == 'backward') directionFactor = -1;
sx = Math.sin(cameraView.rotX);
cx = Math.cos(cameraView.rotX);
sy = Math.sin(cameraView.rotY);
cy = Math.cos(cameraView.rotY);
sz = Math.sin(cameraView.rotZ);
cz = Math.cos(cameraView.rotZ);
// Z-Axis
ztrig = Math.sqrt((cx * cx) + (cy * cy)) * (cx * cy);
cameraView.z = cameraView.z + directionFactor *
(Math.abs(airspeed / 15) * ztrig);
// Y-Axis
ytrig = Math.sqrt((sx * sx) + (cz * cz)) * (sx * cz);
cameraView.y = cameraView.y + directionFactor * …Run Code Online (Sandbox Code Playgroud) 我想在Python中实现Karatsuba的2分割乘法.但是,在表单中写入数字
A=c*x+d
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其中x是基数(let x = b ^ m)接近sqrt(A)的幂.
如果我甚至不能使用除法和乘法,我该如何找到x?我应该计算位数并将A向左移动一半的位数吗?
谢谢.
它看起来像int main(int argc, char *argv[]);.我的问题是:
1我可以添加多少个数组项argv[]?
2每个MAX大小是char *多少?
我有一个python文件,其原始字符串作为docstrings.
def a():
'\n\tthis\n\tis\n\tthe docstring.\n\t'
print 'hello world'
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我如何重写docstring看起来像
def a():
"""
this
is
the docstring.
"""
print 'hello world'
Run Code Online (Sandbox Code Playgroud) 我可以使用 lambda 函数循环遍历类对象列表并更改属性值(对于所有对象或满足特定条件的对象)?
class Student(object):
def __init__(self,name,age):
self.name = name
self.age = age
student1 = Student('StudOne',18)
student2 = Student('StudTwo',20)
student3 = Student('StudThree',29)
students = [student1,student2,student3]
new_list_of_students = map(lambda student:student.age+=3,students)
Run Code Online (Sandbox Code Playgroud) 我和这里有同样的问题,但现在我试图用 python 做同样的事情,因为它更适合这项任务。
我从这个开始:
import os
import shutil
import random
import glob
root_dir = '/home/leonardo/Desktop/python_script/rfe'
output_dir = '/home/leonardo/Desktop/python_script/output_folder'
ref = 200
folders_root_dir = os.listdir(root_dir)
print folders_root_dir
count = len(folders_root_dir)
print count
for i in xrange(count):
folder_inside = root_dir + '/' + folders_root_dir[i]
print folder_inside
number_files_folder_inside = len(os.listdir(folder_inside))
print number_files_folder_inside
if number_files_folder_inside > ref:
ref_copy = round(0.2*number_files_folder_inside)
print ref_copy
# here I have to copy 20% of the files in this folder to the output folder
else:
# here …Run Code Online (Sandbox Code Playgroud) 我有套接字问题
import socket
serverName = "herk-PC"
serverPort = 12000
clientSocket = socket.socket(socket.AF_INET,socket.SOCK_DGRAM)
message = input('input lowercase sentence:')
clientSocket.sendto(message.encode('utf-8'),(serverName, serverPort))
modifiedMessage, serverAddress = clientSocket.recvfrom(2048)
print (modifiedMessage.decode('utf-8'))
clientSocket.close()
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这段代码给我错误
Traceback (most recent call last):
File "J:\Sistem Jaringan\Task I\client.py", line 12, in <module>
modifiedMessage, serverAddress = clientSocket.recvfrom(2048)
ConnectionResetError: [WinError 10054] An existing connection was forcibly closed by the remote host
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我的错误有什么解决办法吗?
这就是我们如何使用Laravel处理多个数据库连接,这是一个PHP框架而不是Python(对于谁来说这是一个重复的帖子)
<?php
return array(
'default' => 'mysql',
'connections' => array(
# Our primary database connection
'mysql' => array(
'driver' => 'mysql',
'host' => 'host1',
'database' => 'database1',
'username' => 'user1',
'password' => 'pass1'
'charset' => 'utf8',
'collation' => 'utf8_unicode_ci',
'prefix' => '',
),
# Our secondary database connection
'mysql2' => array(
'driver' => 'mysql',
'host' => 'host2',
'database' => 'database2',
'username' => 'user2',
'password' => 'pass2'
'charset' => 'utf8',
'collation' => 'utf8_unicode_ci',
'prefix' => '',
), …Run Code Online (Sandbox Code Playgroud)