如何比较2个不同的Pandas数据框的列名。我想比较训练数据帧和测试数据帧，其中测试数据帧中缺少某些列？
当我尝试在 Windows 上的 ubuntu 上的 bash 上安装 g++ 时，出现错误
`
E: Failed to fetch http://security.ubuntu.com/ubuntu/pool/main/l/linux/linux-libc-dev_4.4.0-96.119_amd64.deb 404 Not Found [IP: 91.189.88.152 80]
E: Failed to fetch http://security.ubuntu.com/ubuntu/pool/main/g/glibc/libc6-dev_2.23-0ubuntu9_amd64.deb 404 Not Found [IP: 91.189.88.152 80]
E: Failed to fetch http://security.ubuntu.com/ubuntu/pool/main/g/gcc-5/libstdc++-5-dev_5.4.0-6ubuntu1~16.04.4_amd64.deb 404 Not Found [IP: 91.189.88.152 80]
E: Failed to fetch http://security.ubuntu.com/ubuntu/pool/main/g/gcc-5/g++-5_5.4.0-6ubuntu1~16.04.4_amd64.deb 404 Not Found [IP: 91.189.88.152 80]
E: Failed to fetch http://security.ubuntu.com/ubuntu/pool/main/l/linux/linux-libc-dev_4.4.0-96.119_amd64.deb 404 Not Found [IP: 91.189.88.152 80]
E: Failed to fetch http://security.ubuntu.com/ubuntu/pool/main/g/glibc/libc6-dev_2.23-0ubuntu9_amd64.deb 404 Not Found [IP: 91.189.88.152 80]
E: Failed to fetch …我想转换'edjefe'列的数据,其中包含int以及'yes'和'no'值.我的问题是我只想将'yes'和'no'映射到1和0并保持int值不变所以我写了这段代码
def foo(x):
if x == 'no':
return 0
elif x == 'yes':
return 1
else:
return x
和 df1.edjefe.map(lambda x : foo(x))
但我得到一个错误,因为,
RecursionError: maximum recursion depth exceeded while calling a Python object