以下代码基本上执行以下操作:
我的问题是:是否有更简单,更有效(更快)的方法从文件内容创建字典:
文件:
user1,pass1
user2,pass2
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码
def login():
print("====Login====")
usernames = []
passwords = []
with open("userinfo.txt", "r") as f:
for line in f:
fields = line.strip().split(",")
usernames.append(fields[0]) # read all the usernames into list usernames
passwords.append(fields[1]) # read all the passwords into passwords list
# Use a zip command to zip together the usernames and passwords to create a dict
userinfo = zip(usernames, passwords) # this is a variable that contains the dictionary in the 2-tuple …Run Code Online (Sandbox Code Playgroud) 我创建了一个Web API来呈现带有导航的网页。下面是我的代码
from flask import Flask, render_template, request
app = Flask(__name__)
@app.route('/testsite/')
def home():
return render_template('home.html')
if __name__ == '__main__':
app.run(debug=True)
@app.route('/about/')
def about():
return render_template('about.html')
if __name__ == '__main__':
app.run(debug=True)
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以下是两个html模板的HTML代码
home.html
<!DOCTYPE html>
<html>
<body>
{% extends "layout.html" %}
{% block content %}
<div class="home">
<h1>My Personal Website</h1>
<p>Hi, this is my personal website.</p>
</div>
{% endblock %}
</body>
</html>
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about.html
<!DOCTYPE html>
<html>
<body>
{% extends "layout.html" %}
{% block content %}
<div class="about">
<h1>About me</h1>
<img …Run Code Online (Sandbox Code Playgroud) 我在 python 3.6.5 中使用 Flask-SQLAlchemy 并且 - 到目前为止 - 无法通过调用__init__(). 我的代码如下所示:
'''
file: models.py
'''
from flask_sqlalchemy import SQLAlchemy
db = SQLAlchemy()
class Network(db.Model):
__tablename__ = 'network'
id = db.Column(db.Integer, primary_key=True)
baud_rate = db.Column(db.Integer)
def __init__(**kwargs):
super(Network, self).__init__(**kwargs) # see note
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尝试实例化 Network 对象会导致错误:
>>> n = Network(baud_rate=300)
Traceback (most recent call last):
File "<console>", line 1, in <module>
TypeError: __init__() takes 0 positional arguments but 1 was given
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这有点令人惊讶,因为我使用的是 Flask-SQLAlchemy 文档中给出的配方:
如果您出于任何原因决定覆盖构造函数,请确保继续接受 **kwargs 并使用这些 **kwargs …
我有一个简单的python文件,尝试将其设置为使用会话,当我运行该文件时,出现以下错误:
ModuleNotFoundError:没有名为“ flask_session”的模块
我相信我已正确导入了模块,是否还有其他可以检查以正确设置的模块?
from flask import Flask, render_template, request, session
from flask_session import Session
app = Flask(__name__)
app.config["SESSION_PERMANENT"] = False
app.config["SESSION_TYPE"] = "filesystem"
Session(app)
@app.route("/", methods=["GET", "POST"])
def index():
if session.get("notes") is None:
session["notes"] = []
if request.method == "POST":
note = request.form.get("note")
session["notes"].append(note)
return render_template("index.html", notes=notes)
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这是回溯(最近一次拨打电话)
File "c:\python37\lib\site-packages\flask\cli.py", line 325, in __call__
Open an interactive python shell in this frameself._flush_bg_loading_exception()
File "c:\python37\lib\site-packages\flask\cli.py", line 313, in _flush_bg_loading_exception
reraise(*exc_info)
File "c:\python37\lib\site-packages\flask\_compat.py", line 35, in reraise
raise value
File "c:\python37\lib\site-packages\flask\cli.py", …Run Code Online (Sandbox Code Playgroud) 我正在尝试用 python 制作游戏,但遇到了根据游戏中的动作让对象切换状态的问题。
我发现最好的方法是使用某种方法将函数(对象的状态)定义为变量,并根据操作赋予对象一个状态。不幸的是,我不确定这是否可行,或者在谈到这个主题时可能有一个我还没有学习的概念。如果有人可以为我的问题提供解决方案,或者只是指出我学习解决问题的方法的方向。
有没有办法将某些函数/方法与名称相关联并避免多个if语句?
class stateUser:
def __init__(self,state):
self.state = state
def executeState(self):
if self.state == "Print Something":
self.printSomething()
elif self.state == "Not Print Something":
self.dontPrint()
else:
self.notUnderstand()
'''
would like this function to simply call
a function that is defined as the object's state,
instead of using a bunch of if statements
'''
def printSomething(self):
print("Something")
def dontPrint(self):
print("No")
def notUnderstand(self):
print("I didn't understand that")
runner = stateUser(None)
a = True
while a:
runner.state = input("Enter …Run Code Online (Sandbox Code Playgroud) 使用BeautifulSoul和Python,我希望find_all所有tr匹配给定类属性的项目包含多个名称,如下所示:
<tr class="admin-bookings-table-row bookings-history-row paid ">
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我已经尝试了几种匹配该类的方法.正则表达式,通配符,但我总是得到一个空列表.
有没有办法使用正则表达式,通配符或如何匹配此类?
还有就是贴了同样的问题在这里没有答案.
我正在尝试使用Python上的PuLP 来解决这个问题http://www.me.utexas.edu/~jensen/ORMM/models/unit/linear/subunits/workforce/.
这是我的代码:
from pulp import *
# Create the 'prob' variable to contain the problem data
prob = LpProblem("The Bus Problem",LpMinimize)
# The variables are created with a lower limit of zero
x0=LpVariable("Number of drivers at time 0",0,None,LpInteger)
x4=LpVariable("Number of drivers at time 4",0)
x8=LpVariable("Number of drivers at time 8",0)
x12=LpVariable("Number of drivers at time 12",0)
x16=LpVariable("Number of drivers at time 16",0)
x20=LpVariable("Number of drivers at time 20",0)
# The objective function is added to 'prob' first …Run Code Online (Sandbox Code Playgroud) 您好,我尝试使用 YouTube 数据 API 从 YouTube 视频下载字幕。我自定义了YouTube 生成的示例代码。
#!/usr/bin/python
# Usage example:
# python captions.py --videoid='<video_id>' --name='<name>' --file='<file>' --language='<language>' --action='action'
import httplib2
import os
import sys
from apiclient.discovery import build_from_document
from apiclient.errors import HttpError
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import argparser, run_flow
# The CLIENT_SECRETS_FILE variable specifies the name of a file that contains
# the OAuth 2.0 information for this application, including its client_id and
# client_secret. You can acquire …Run Code Online (Sandbox Code Playgroud) 说 list(x) = ["12/12/12", "Jul-23-2017"]
我想计算字母的数量(在这种情况下是 0)和数字的数量(在这种情况下是 6)。
我尝试调用x[i].isalpha()并x[i].isnumeric()在迭代 for 循环时抛出错误说明
“类型错误:列表索引必须是整数或切片,而不是 str”
任何帮助将不胜感激!
python ×9
flask ×3
python-3.x ×3
dictionary ×1
file ×1
oauth ×1
oop ×1
pulp ×1
python-2.7 ×1
youtube ×1