小编N0v*_*0va的帖子

我有以下代码来生成基于interp1d离散数据的插值的streamplot:

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.colors as colors
from scipy.interpolate import interp1d

# CSV Import
a1array=pd.read_csv('a1.csv', sep=',',header=None).values
rv=a1array[:,0]
a1v=a1array[:,1]
da1vM=a1array[:,2]
a1 = interp1d(rv, a1v)
da1M = interp1d(rv, da1vM)

# Bx and By vector components
def bx(x ,y):
    rad = np.sqrt(x**2+y**2)
    if rad == 0:
        return 0
    else:
        return x*y/rad**4*(-2*a1(rad)+rad*da1M(rad))/2.87445E-19*1E-12

def by(x ,y):
    rad = np.sqrt(x**2+y**2)
    if rad == 0:
        return 4.02995937E-04/2.87445E-19*1E-12
    else:
        return -1/rad**4*(2*a1(rad)*y**2+rad*da1M(rad)*x**2)/2.87445E-19*1E-12

Bx = np.vectorize(bx, otypes=[np.float])
By …