小编use*_*878的帖子

如何以这样的格式转换PHP数组

Array
(
    [0] => 001-1234567
    [1] => 1234567
    [2] => 12345678
    [3] => 12345678
    [4] => 12345678
    [5] => AP1W3242
    [6] => AP7X1234
    [7] => AS1234
    [8] => MH9Z2324
    [9] => MX1234
    [10] => TN1A3242
    [11] => ZZ1234
)

以下面的格式的Javascript数组？

var cities = [
    "Aberdeen",
    "Ada",
    "Adamsville",
    "Addyston",
    "Adelphi",
    "Adena",
    "Adrian",
    "Akron",
    "Albany"
];

这是我的zend查询

return $this->fetchRow($this->select()->where('name = ?', $geofence_name) );

我想在我的查询中添加另一个过滤器,因为我想检查另一个条件.

请指导我.

在我的项目中,我维护着不同的jquery版本.所以,我得到jquery冲突请帮我解决这个问题.