小编Lyn*_*ndz的帖子

我试图使用ggplot在一个时间序列中绘制多个趋势线(每十年).

这是数据:

dat <- structure(list(YY = 1961:2010, a = c(98L, 76L, 83L, 89L, 120L, 
107L, 83L, 83L, 92L, 104L, 98L, 91L, 81L, 69L, 86L, 76L, 85L, 
86L, 70L, 81L, 77L, 89L, 60L, 80L, 94L, 66L, 77L, 85L, 77L, 80L, 
79L, 79L, 65L, 70L, 80L, 87L, 84L, 67L, 106L, 129L, 95L, 79L, 
67L, 105L, 118L, 85L, 86L, 103L, 97L, 106L)), .Names = c("YY", 
"a"), row.names = c(NA, -50L), class = "data.frame")

这是脚本:

p <- ggplot(dat, aes(x = YY))
p <- p …

我试图使用ggplot绘制自举样本(1000列),但结果图不正确.

这是数据:

dat<- structure(list(YY = c(1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 1961L, 
1961L, 1961L, 1961L, 1961L, 1961L, 1961L, …

我正在尝试使用下面的代码在 R 中绘制月度玫瑰图，但遇到错误：“错误：分面变量必须至少有一个值”

这是我使用的 数据链接到数据

此代码来自上一篇文章：使用 ggplot 的玫瑰图

require(ggplot2)
require(RColorBrewer)
require(scales)

plot.windrose <- function(data,
                      spd,
                      dir,
                      spdres = 2,
                      dirres = 22.5,
                      spdmin = 2,
                      spdmax = 20,
                      spdseq = NULL,
                      palette = "YlGnBu",
                      countmax = NA,
                      debug = 0){


  # Look to see what data was passed in to the function
  if (is.numeric(spd) & is.numeric(dir)){
  # assume that we've been given vectors of the speed and direction vectors
   data <- data.frame(spd = spd,
                   dir = dir)
   spd = …