小编Mun*_*y V的帖子

如何在线程间通信中调用特定线程？

在下面的程序中,我有两个线程t1和t2.

当我称之为t1.notify()加薪:

Exception in thread "Thread-1" java.lang.IllegalMonitorStateException
    at java.lang.Object.notify(Native Method)
    at Shared.methodTwo(NotifyThread.java:43)
    at Thread2.run(NotifyThread.java:77)
Error 

class Shared {

    Thread1 t1 ;
    Thread2 t2 ;

    void ThreadInit( Thread1 t1 , Thread2 t2 ) {
        this.t1 = t1 ;
        this.t2 = t2 ;
    }

    synchronized void methodOne()
    {
        Thread t = Thread.currentThread();

        System.out.println(t.getName()+" is relasing the lock and going to wait");

        try
        {
            wait();        //releases the lock of this object and waits
        }
        catch (InterruptedException …

#include<stdio.>

int main() {
    signed x;
    unsigned y;

    x = 10 +- 10u + 10u +- 10;
    y = x;
    if(x==y)
        printf("%d %d",x,y);
    else if(x!=y)
        printf("%u  %u",x,y);
    return 0;
}

我无法理解上述程序的流程.请解释编译器如何-10u视为默认值.从我的理解10u是无符号的,但在这个程序中它自动将其转换为-10.

http://www.cquestions.com/2012/02/data-type-questions-in-c.html,问题编号.3.