小编jos*_*123的帖子

Java 比较问题 - 比较方法违反了其一般契约

我正在尝试对一些数字进行排序。我收到“java.lang.IllegalArgumentException:比较方法违反了其一般契约!” 当我执行以下代码时出现异常。

import org.apache.commons.lang3.StringUtils;

public class ComparatorTest {

    public static void main(String[] args) {
        List<String> ll = List.of("1.A", "1.A.1", "10.A", "10.A.1", "10.A.2", "10.A.3", "12.A", "12.A.1", "12.A.2",
                "12.A.4", "12.A.6", "1A.2", "2.A.1", "2.A.1.b", "2.A.1.b.1", "2.A.1.b.2", "2.A.1.b.3", "20.A.1",
                "20.A.1.a", "20.A.1.b", "20.A.1.b.1", "20.A.1.b.2", "3.A.1", "3.A.1.a", "3.A.1.a.1", "3.A.1.a.2",
                "3.A.1.a.3", "3.A.1.a.4", "3.A.1.b", "3.A.10", "6.A.1", "9.A.1");
        
        ArrayList<String> l2 = new ArrayList<>(ll);
        Collections.sort(l2, (obj1, obj2) -> {
            try {
                String[] prodClass1 = obj1.split("\\.");
                String[] prodClass2 = obj2.split("\\.");
                for (int i = 0; (i < prodClass1.length) && (i < …
Run Code Online (Sandbox Code Playgroud)

java sorting comparator java-8

-1
推荐指数
1
解决办法
106
查看次数

标签 统计

comparator ×1

java ×1

java-8 ×1

sorting ×1