小编Gra*_*gon的帖子

我正在为MobX 看这个小提琴,我也看到了这两种在ES6其他地方定义React Components的方法,比如Dan Abramov的egghead redux视频系列.

@observer
class TodoListView extends Component {
    render() {
        return <div>
            <ul>
                {this.props.todoList.todos.map(todo => 
                    <TodoView todo={todo} key={todo.id} />
                )}
            </ul>
            Tasks left: {this.props.todoList.unfinishedTodoCount}
        </div>
    }
}

const TodoView = observer(({todo}) =>
    <li>
        <input
            type="checkbox"
            checked={todo.finished}
            onClick={() => todo.finished = !todo.finished}
        />
        <input
            type="text"
          value={todo.title}
          onChange={ e => todo.title = e.target.value } />
    </li>
);

我的问题是,什么时候适合使用每种类型？

似乎更简单的组件能够使用更简单的语法,但我希望遵循规则或准则.

谢谢!

我无法让PIL放大图像.大图像缩小得很好,但小图像不会变大.

# get the ratio of the change in height of this image using the
# by dividing the height of the first image
s = h / float(image.size[1])
# calculate the change in dimension of the new image
new_size = tuple([int(x*s) for x in image.size])
# if this image height is larger than the image we are sizing to
if image.size[1] > h: 
    # make a thumbnail of the image using the new image size
    image.thumbnail(new_size)
    by = "thumbnailed" …

我正在使用angular-ui-router在bootstrap和angular中编写一个下拉导航.当链接有下拉列表时,链接应为空白.但是,如果我将一条空白路径传递给ui-sref,我会收到错误消息.

这是一段代码片段:

<ul class="dropdown-menu">
  <li ng-repeat="button in buttons" id="foo" ng-class="{'dropdown-submenu': $index=button.hasLinks}" >
    <a ui-sref="{{button.route}}" title="{{ button.text }} Tab" class="{ dropdown-toggle: button.links }" data-toggle="dropdown">
      <i class="icon icon-{{ button.icon }}"></i> {{ button.text }}
    </a>
    <ul class="dropdown-menu">
      <li ng-repeat="link in button.links">
        <a ng-href="{{ link.route }}" title="{{ link.text }} Tab">
          {{ link.text }}
        </a>
      </li>
    </ul>
  </li>
</ul>

只是想知道在python中是否有更聪明,更短的方式来编写它.

y = False
x = not y

在javascript中我会:

y = false,
x = !y

谢谢!