小编FGx*_*tta的帖子

我是java编程的初学者.我正在尝试重新创建卡片游戏大战的简化版本.我运行了下面发布的程序,它返回了这个错误:

线程"main"java.lang.NullPointerException中的异常

在cardgame.BuildDeck(cardgame.java:36)

在cardgame.main(cardgame.java:60)

我一直试图通过研究自己解决这个问题,但我无法解决.我想知道是否有人可以帮助我.如果您确实需要有关我的计划的任何其他信息,请询问.提前致谢!

-FGxMatta

public class cardgame 
{
static class TheCard
{
    // Java getter & setter
    private String CardName;
    private int CardRank;
    private int Chosen;

    public TheCard(int rank, String name)
    {
        this.CardName = name;
        this.CardRank = rank;
        this.Chosen = 0;
    }
}


@SuppressWarnings("null")
private static TheCard[] BuildDeck()
{
    TheCard[] TheDeck = null;
    String[] Cards =  {"2","3","4","5","6","7","8","9","10","Jack","Queen","King","Ace"};
    String[] Suits = {"Spades","Hearts","Diamonds","Clubs"};
int[] Rank = {2,3,4,5,6,7,8,9,10,11,12,13,14};
    int cardnumber = 0;
    for (int i = 0; i < Cards.length; i++) …

我的第一个循环似乎正确地构建了数组,当我在第二个"for"循环中打印出结果时,它会立即终止.我看不出错误.这是代码:

public class CoinFlip 
{
    private static int Flip()
    {
        return (int)(2*Math.random());   //returns 0 or 1; 0=Tails,1=Heads 
    }
    public static void main(String args[])
    {
        int HEADS = 1;
        int[] ConsecArray = new int[1000];   // the odds of ever having more than 1000 HEADS consecutively flipped are nil
        int Sequencecounter = 0;
        for (int i = 0; i < ConsecArray.length; i++)
        {
            if (Flip() == HEADS)
            {
                Sequencecounter++;
            }
            else    // we have a TAILS
            {
                // Check sequence counter, if …