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取消引用 void * 指针、结构数组

我正在尝试将 void * 指针更改为结构数组。\n重点是将全局可见指针初始化为 NULL,当 main 启动时,该指针将转换为结构数组\n 这是一个最小的示例。

\n\n
#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n\nvoid * hashtable;\n\nstruct bucket {\n    int a;\n    int b;\n};\n\nint main (void)\n{\n    hashtable = (struct bucket)malloc(6*sizeof(struct bucket));\n    int i ;\n    //for(i=0;i<6;i++)\n    //  hashtable[i] =  malloc(sizeof(struct bucket));\n\n    *(struct bucket)hashtable[0]->a = 12;\n\n    return 0;\n}\n
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我得到的错误是:

\n\n
test.c:16:52: error: conversion to non-scalar type requested\n  hashtable = (struct bucket)malloc(6*sizeof(struct bucket));\n                                                ^\ntest.c:21:27: warning: dereferencing \xe2\x80\x98void *\xe2\x80\x99 pointer\n  *(struct bucket)hashtable[0]->a = 12;\n                       ^\ntest.c:21:27: error: void value not ignored as it ought to be\n
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