我跟着: Node Beginner Book
使用另一个SO帖子的代码测试后:
var Fs = require('fs');
var dirs = ['tmp'];
var index;
var stats;
for (index = 0; index < dirs.length; ++index)
{
try
{
stats = Fs.lstatSync(dirs[index]);
console.log(dirs[index] + ": is a directory? " + stats.isDirectory());
}
catch (e)
{
console.log(dirs[index] + ": " + e);
}
}
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错误仍然存在:
错误:ENOENT,没有这样的文件或目录'tmp'
tmp的权限是777.
requestHandlers.js
var querystring = require("querystring"),
fs = require("fs");
function start(response, postData) {
console.log("Request handler 'start' was called.");
var body = '<html>'+
'<head>'+
'<meta http-equiv="Content-Type" '+ …
Run Code Online (Sandbox Code Playgroud) 我无法调试此问题或在线查找解决方案.Node.js的新手,希望有人能提供解决方案
错误:更新了控制台日志信息2012年2月11日星期六上午7:27:17
Request for/ received!
About to route a request for /
Request handler 'start' was called.
Request for/favicon.ico received!
About to route a request for /favicon.ico
No request handler found for /favicon.ico
Request for/favicon.ico received!
About to route a request for /favicon.ico
No request handler found for /favicon.ico
Request for/upload received!
About to route a request for /upload
Request handler 'upload' was called.
about to parse
{ output: [],
outputEncodings: [],
writable: true,
_last: false, …
Run Code Online (Sandbox Code Playgroud) <?php # Nettuts Tutorial using PHP Data Objects (PDO),
/**This file contains the database access information
*This file also establishes a connection to mySQL
*and selects the database.
*Set the database access information as constants:
**/
// print_r(PDO::getAvailableDrivers());
DEFINE('DB_USER', 'root');
DEFINE('DB_PASSWORD', 'root');
DEFINE('DB_HOST', 'localhost');
DEFINE('DB_NAME', 'sitename');
$php = "htmlspecialchars";
try {
#MySQL with PDO_MYSQL
// $DBH = new PDO("mysql:host={$php(DB_HOST)}; dbname={$php(DB_NAME)}", root, root};
$DBH = new PDO("mysql:host=localhost; dbname= sitename", root, root);
$DBH->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
# UH-OH! Typed DELECT instead of SELECT!
$DBH->prepare('DELECT …
Run Code Online (Sandbox Code Playgroud) 来自:Pro PHP和jQuery:
■提示返回的值是CSS简写属性.3 jQuery的一个额外好处是能够使用CSS简写设置CSS属性,这在使用基本JavaScript时无效.
来自jQuery API参考:
不支持速记CSS属性(例如边距,背景,边框).例如,如果要检索渲染边距,请使用:$(elem).css('marginTop')和$(elem).css('marginRight'),依此类推.
我很困惑,可以设置css速记,但不能读?当然我只会使用样式表,但问题是学术启发.
以下片段引起了
"PHP Parse错误:语法错误,/ Applications/MAMP/htdocs3/nettuts/PHP/PDO for Database Access/htdocs/view_users02.php第39行意外结束"
我环顾了网站和谷歌,但没有找到确切的解决方案.
foreach($DBH->query($sql) as $row){
$output = "<tr><td align='left'>" . $row["name"] . "</td><td align='left'>" . $row["dr"] . "</td></tr>";
// echo '<tr><td align="left">' . $row['name'] . '</td><td align="left">' . $row['dr'] . '</td></tr>';
echo <<<EOT
$output
EOT;
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完整的脚本
<?php
$page_title = 'View the Current Users';
include ('includes/header.html');
// Page header:
echo '<h1>Registered Users</h1>';
require_once ('../mysql_pdo_connect.php'); // Connect to the db.
// Make the query:
$sql = "SELECT CONCAT(last_name, ', ', first_name) AS name, DATE_FORMAT(registration_date, '%M %d, …
Run Code Online (Sandbox Code Playgroud) 在下面的代码片段中,我不确定如何将RegEx分配给match(),是否总是需要RegEx?:
- - - - - 比赛 - - - - - -
case 'remove':
var rep=o.className.match(' '+c1)?' '+c1:c1;
o.className=o.className.replace(rep,'');
break;
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------全 - 代码--------------
function cssjs(a,o,c1,c2){
switch (a){
case 'swap':
if(!domtab.cssjs('check',o,c1)){
o.className.replace(c2,c1)
}else{
o.className.replace(c1,c2);
}
break;
case 'add':
if(!domtab.cssjs('check',o,c1)){
o.className+=o.className?' '+c1:c1;
}
break;
case 'remove':
var rep=o.className.match(' '+c1)?' '+c1:c1;
o.className=o.className.replace(rep,'');
break;
case 'check':
var found=false;
var temparray=o.className.split(' ');
for(var i=0;i<temparray.length;i++){
if(temparray[i]==c1){found=true;}
}
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