小编Jon*_*Jon的帖子

我想让我的格式为2016-07-08T00:00:00.000Z.

String myDate = "20160708";
LocalDate myLocalDate = LocalDate.parse(myDate, DateTimeFormatter.BASIC_ISO_DATE);
OffsetDateTime myOffsetDate = myLocalDate.atTime(OffsetTime.now(ZoneOffset.UTC));

System.out.println(myOffsetDate); //2016-07-08T14:58:23.170Z

我有一些名称中带有点的元素，如下所示，我收到“语法错误，无法识别的表达式”。有没有办法针对这些目标？

cy.get('input[name=foo.bar]')

我正在尝试获取p标签,但尚未成功.以下是我想要获得的数据.

  for $i in $data
    let $ptag := $i//*[p]/text()

  (: $data example :)
  <div xmlns="http://www.w3.org/1999/xhtml">
    <div class="title">my title</div>
    <div class="course">
      <div class="room">112</div>
      <div class="teacher">Mr. Wilson</div>
      <div class="student">123456</div>
      <p>approved</p>
    </div>
  </div>

如果它是最后一项,我试图在大括号后没有逗号.

  for $row in /md:row
  let $test := $row/md:test/text()
  let $last := $row/*[fn:position() = fn:last()]

  return (
   '{
    "test": {
    "type": "test",
    "test": [',$testa,',',$testb,']
    }      
   }',
   if($last)
   then ''
   else (',')
  )