小编Nik*_*kaE的帖子

array1 = array1.filter{ $0.arrayInsideOfArray1.contains(array2[0]) }

上面的代码有效,但我试图检查$ 0.arrayInsideOfArray1的所有元素是否与array2的所有元素匹配,而不仅仅是[0]

例:

struct User {
    var name: String!
    var age: Int!
    var hasPet: Bool!
    var pets: [String]!
}

var users: [User] = []

users.append(User(name: "testUset", age: 43, hasPet: true, pets: ["cat", "dog", "rabbit"]))
users.append(User(name: "testUset1", age: 36, hasPet: true, pets:["rabbit"]))
users.append(User(name: "testUset2", age: 65, hasPet: true, pets:["Guinea pigs", "Rats"]))

let petArr = ["cat", "dog", "rabbit"]

users = users.filter { $0.pets.contains(petArr[0]) }

我想要的是petArr中列出任何宠物的任何用户!