小编Goo*_*dea的帖子

我正在新服务器上安装以前构建的网站.我不是原来的开发者.

我过去使用了Gunicorn + nginx来保持应用程序的活着(基本上遵循本教程),但我在这里遇到问题.

我source venv/bin/activate,然后./manage.py runserver 0.0.0.0:8000运作良好,一切都按预期运行.我将其关闭并运行gunicorn --bind 0.0.0.0:8000 myproject.wsgi:application,并获得以下信息:

[2016-09-13 01:11:47 +0000] [15259] [INFO] Starting gunicorn 19.6.0
[2016-09-13 01:11:47 +0000] [15259] [INFO] Listening at: http://0.0.0.0:8000 (15259)
[2016-09-13 01:11:47 +0000] [15259] [INFO] Using worker: sync
[2016-09-13 01:11:47 +0000] [15262] [INFO] Booting worker with pid: 15262
[2016-09-13 01:11:47 +0000] [15262] [ERROR] Exception in worker process
Traceback (most recent call last):
  File "/var/www/myproject/venv/lib/python3.5/site-packages/gunicorn/arbiter.py", line 557, in spawn_worker
    worker.init_process()
  File "/var/www/myproject/venv/lib/python3.5/site-packages/gunicorn/workers/base.py", line 126, in …

是否可以编写一个接受字符串常量作为其参数之一的接口，并将其用作对象的键？

例如，假设我发出两个不同的 GraphQL 请求，它们都返回 a User，但键名不同：

const userByIdResult = {
  data: {
    userById: {
       id: 123,
       username: 'joseph'
    }
  }
}

const userByUsernameResult = {
  data: {
    userByUsername: {
       id: 123,
       username: 'joseph'
    }
  }
}

我想写一个通用接口会是这样的：

interface GraphQLResponse<QueryKey, ResponseType> {
  data: {
    [QueryKey]: ResponseType
  }
}

interface User {
    username: string
    id: string
}

type UserByIdResponse = GraphQLResponse<'userById', User>
type UserByUsernameResponse = GraphQLResponse<'userByUsername', User>

但是，这行不通。

如果我的GraphQL架构中有多个类型共有的字段集,有没有办法做这样的事情？

type Address {
  line1: String
  city: String
  state: String 
  zip: String
}

fragment NameAndAddress on Person, Business {
  name: String
  address: Address
}

type Business {
   ...NameAndAddress
   hours: String
}

type Customer {
   ...NameAndAddress
   customerSince: Date
}

每当我array.map在元组上使用时，Typescript 都会将其推断为通用数组。例如，这里有一些简单的 3x3 数独游戏：

const _ = ' ' // a "Blank"

type Blank = typeof _

type Cell = number | Blank

type Three = [Cell, Cell, Cell]

type Board = [Three, Three, Three]

const initialBoard: Board = [
    [_, 1, 3],
    [3, _, 1],
    [1, _, _],
]

// Adds a `2` to the first cell on the first row
function applyMove(board: Board): Board {
    // errors here
    const newBoard: Board =  board.map((row: Three, index: number) …