我很感激有关如何在 SQL 中检查一个列表中的元素是否也出现在另一个列表中的任何指示。
List A = Live Customers in April
List B = Live Customers in May
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如何检查列表 A 中的哪些客户也出现在列表 B 中?识别丢失的客户
i.e. Customers in A but not in B.
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感谢您的帮助。加夫
有没有办法在 CASE 语句中将 CAST 转换为 INTEGER ?
CASE
WHEN SV.END_DATE IS NOT NULL THEN SV.END_DATE - SV.START_DATE
ELSE 0
END AS DAYDIFF
Run Code Online (Sandbox Code Playgroud) 如果当前CLUSTERn =上一个CLUSTERn,然后将上一个PRODCAT作为PREVCAT添加到当前行,那么我的case语句出了什么问题,我将不胜感激。
ORA-30484: missing window specification for this function
30484. 00000 - "missing window specification for this function"
*Cause: All window functions should be followed by window specification,
like <function>(<argument list>) OVER (<window specification>)
*Action:
Error at Line: 11 Column: 30
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SELECT CLUSTERn,
MEMBERn,
COUNT(*) OVER ( PARTITION BY CLUSTERn ORDER BY MEMBERn, PRODCAT, STARTd, ENDd ) AS NEWRANK,
CASE WHEN CLUSTERn = LAG(CLUSTERn) THEN LAG(PRODCAT) ELSE 'New' END AS PREVCAT,
STATUS,
PRODCAT,
JOINTYPE,
JOINRANK,
CSP,
PROGID,
PROMNAME,
PROMOID,
COHORT, …Run Code Online (Sandbox Code Playgroud)