public String[][] fetchData()
{
String[][] data = null;
int counter = 0;
while (counter < 10){
data[counter] = new String[] {"abc"};
counter++;
}
return data;
}
在此循环中获取错误.请让我知道我错在哪里
我正在opencv写一个面部表演程序.这是下面的错误代码:
result = img[rects[0]:rects[1], rects[2]:rects[3]]
result = cv2.resize(result, (100,100))
img是我们的原始图片,第一步是将我们对结果感兴趣.第二步是调整为100*100像素.
错误是:
result = cv2.resize(result, (100,100))
error: ..\..\..\src\opencv\modules\imgproc\src\imgwarp.cpp:1725: error: (-215) ssize.area() > 0
希望可以有人帮帮我.非常感谢.
下面是从对象列表中查找重复对象的代码.但由于某种原因,hashset甚至存储了相等的对象.
我肯定错过了一些东西,但是当我检查hashset的大小时,它出来了5.
import java.util.ArrayList;
import java.util.HashSet;
public class DuplicateTest {
public static void main(String args[]){
ArrayList<Dog> dogList = new ArrayList<Dog>();
ArrayList<Dog> duplicatesList = new ArrayList<Dog>();
HashSet<Dog> uniqueSet = new HashSet<Dog>();
Dog a = new Dog();
Dog b = new Dog();
Dog c = new Dog();
Dog d = new Dog();
Dog e = new Dog();
a.setSize("a");
b.setSize("b");
c.setSize("c");
d.setSize("a");
e.setSize("a");
dogList.add(a);
dogList.add(b);
dogList.add(c);
dogList.add(d);
dogList.add(e);
if(a.equals(d)){
System.out.println("two dogs are equal");
}
else System.out.println("dogs not eqal");
for(Dog dog : dogList){
uniqueSet.add(dog); …我正在使用蓝牙将一个约500MB的大文件从一个系统传输到另一个系统。在这段时间里，我将看到一个气球弹出窗口，上面显示“ Bluetooth Connection”（蓝牙连接），其内容是模式已更改为高速模式。我想使用python在变量中获取此文本。关于如何从气球弹出窗口中读取文本的任何线索？
希望尽快得到答复。
关于辛
试图在#6创建的列表的#7中对角地获得总和.所以说清单是这个[[2,3,1],[1,1,1],[5,6,4]]总和将是2 + 1 + 4
#6
def randomlists(s):
b=s
list1 = []
while s>0:
sublist = []
for x in range(0,b):
sublist.append(randrange(-100,101))
list1.append(sublist)
s-=1
return list1
#print(randomlists(5))
#7
def diagonalsum(x):
a=randomlists(x)
count=0
print (a)
for b in a:
while count<x:
d=a[0]
b=a[1]
c=a[2]
print (a[(count)])
count+=1
return d+b+c
print (diagonalsum(3))
我正在创建一个显示图表的页面,具体取决于在组合框中选择的类型
<div id="chartdiv"></div>
<select name="graphe" id="identifiantDeMonSelect">
<option value="Column2D">Column2D
<option value="Column3D">Column3D
<option value="Pie3D">Pie3D
<option value="Pie2D">Pie2D
</select>
<input type="submit" value="Afficher" onclick="ajax()">
<script type="text/javascript">
function ajax(){
var xhr
if (window.XMLHttpRequest) {
xhr = new XMLHttpRequest();
}
else if (window.ActiveXObject)
{
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
if (xhr !=null) {
xhr.onreadystatechange = function() { type1(xhr); };
xhr.open("GET", "{{ path('Ajax')}}", true);
xhr.send(null);
} else {
alert("The XMLHttpRequest not supported");
}}
function type1(xhr){
var docXML= xhr.responseText;
var val_type = getSelectValue('identifiantDeMonSelect');
var type = val_type+"";
var str="{{ …我有一个像这样的元组列表:
[('Ben', '5 0 0 0 0 0 0 1 0 1 -3 5 0 0 0 5 5 0 0 0 0 5 0 0 0 0 0 0 0 0 1 3 0 1 0 -5 0 0 5 5 0 5 5 5 0 5 5 0 0 0 5 5 5 5 -5'),
('Moose', '5 5 0 0 0 0 3 0 0 1 0 5 3 0 5 0 3 3 5 0 0 0 …我想知道使用的利弊Arrays.asList.我在代码中使用它时遇到了问题.
另外,我想知道在不使用的情况下将数组转换为数组列表(集合)的最佳方法 Arrays.asList
Python 3。我试图返回该函数，以便它需要一个单词并将其转换为 Cow Latin。我想在运行函数时去掉方括号、逗号和单撇号。
我的职能是：
alpha = list("bcdfghjklmnpqrstvwxyz")
def cow_latinify_word(word):
if word[0].lower() in alpha:
lista = (word.lower())
return lista[1:] + lista[0] + "oo"
else:
return word + "moo"
def cow_latinify_sentence(sentence):
words = sentence.split();
return [cow_latinify_word(word) for word in words]
当我测试该功能时
cow_latin = cow_latinify_sentence("Cook me some eggs")
print(cow_latin)
我得到['ookcoo', 'emoo', 'omesoo', 'eggsmoo']但我想要ookcoo emoo omesoo eggsmoo
这让我很难过......
<!DOCTYPE html>
<html>
<head>
<meta charset=utf-8 />
<title>JS Bin</title>
<style>
.slide-nav:nth-of-type(1) { color:red } /* this should select the number 1 */
</style>
</head>
<body>
<div class="image">
<span class="slide" data-order="4" rel="content-images/teta.jpg" ></span>
<span class="slide" data-order="3" rel="content-images/champ.jpg" ></span>
<span class="slide" data-order="2" rel="content-images/clouds.jpg" ></span>
<img class="slide initial" data-order="1" src="content-images/air.jpg" />
<span class="spinner"></span>
<!--
delete this line to comment the two arrow links -->
<a class="arrow next" href="javascript:void(0)">→</a>
<a class="arrow prev" href="javascript:void(0)">←</a>
<!-- -->
<a class="slide-nav on" href="javascript:void(0)" rel="1">1</a>
<a class="slide-nav" …我在C#上做了一个练习,这里是:
class Program
{
static double funk(int a, ref int b)
{
double c = a + b;
a = 5;
b = a * 3;
return c;
}
static void Main(string[] args)
{
int a = 1, b = 2;
Console.WriteLine(funk(a, ref b));
Console.WriteLine(a);
Console.WriteLine(b);
Console.ReadLine();
}
因此,当我运行代码时结果非常清楚,它给了我:
3
1
15
我现在的问题是,15和3来自哪里？
python ×5
java ×3
arrays ×2
2d ×1
balloon-tip ×1
bluetooth ×1
c# ×1
collections ×1
css ×1
diagonal ×1
equals ×1
hashset ×1
html ×1
javascript ×1
opencv ×1
python-2.7 ×1
python-3.x ×1
string ×1
sum ×1
twig ×1