小编pan*_*osl的帖子

我有一个日期时间对象列表,我想找到最老或最年轻的对象.其中一些日期可能在将来.

from datetime import datetime

datetime_list = [
    datetime(2009, 10, 12, 10, 10),
    datetime(2010, 10, 12, 10, 10),
    datetime(2010, 10, 12, 10, 10),
    datetime(2011, 10, 12, 10, 10), #future
    datetime(2012, 10, 12, 10, 10), #future
]

什么是最佳方式？我在考虑将datetime.now()与其中的每一个进行比较.

我有两个这样的模型:

class Schedule(models.Model):
    name = models.CharField(_('name'), blank=True, max_length=15)


class Day(models.Model):
    DAYS_OF_THE_WEEK = (
        (0, _('Monday')),
        (1, _('Tuesday')),
        (2, _('Wednesday')),
        (3, _('Thursday')),
        (4, _('Friday')),
        (5, _('Saturday')),
        (6, _('Sunday')),
    )
    schedule = models.ForeignKey(Schedule, blank=True, null=True, verbose_name=_('schedule'))
    day = models.SmallIntegerField(_('day'), choices=DAYS_OF_THE_WEEK)
    opening = models.TimeField(_('opening'), blank=True)
    closing = models.TimeField(_('closing'), blank=True)

计划可能有两个Day对象,如下所示:

Day(schedule = 1,day = 0,opening = datetime.time(7,30),closing = datetime.time(10,30))Day(schedule = 1,day = 0,opening = datetime.time(12, 30),closing = datetime.time(15,30))

喜欢同一天不同的班次.

如果我现在迭代它们,我会得到第0天的两个条目,就像这样[日程安排] [0,0,1,2,3,4,5,6]

如何创建一个查询集,以便它将相同的日期组合在一起并保留其属性？

[day for day in schedule]
[0 (two entries), 1, 3, 4, …