小编aar*_*207的帖子

我需要获取以所需字母开头的所有文件,我正在尝试使用->where过滤器添加'like'为运算符但通配符不起作用.

        $files = File::files(storage_path($id_files));
        $files = collect($files);
        $files->transform(function ($item, $key){
            $item->public_filename = $item->getFilename();
            return $item;
        });

这是我们的目标数据,我需要创建一个public_filename应用过滤器的字段.我们的文件(dd($files)):

   Collection {#503 ?
  #items: array:3 [?
    0 => SplFileInfo {#525 ?
      -relativePath: ""
      -relativePathname: "atxt.txt"
      path: "/home/vagrant/Code/project/storage/app/uploads/general"
      filename: "atxt.txt"
      basename: "atxt.txt"
      pathname: "/home/vagrant/Code/project/storage/app/uploads/general/atxt.txt"
      extension: "txt"
      realPath: "/home/vagrant/Code/project/storage/app/uploads/general/atxt.txt"
      aTime: 2017-09-29 09:51:17
      mTime: 2017-09-27 14:39:11
      cTime: 2017-09-27 14:39:11
      inode: 32833
      size: 3
      perms: 0100777
      owner: 1000
      group: 1000
      type: "file"
      writable: true
      readable: true
      executable: true
      file: …