小编Hrv*_*jar的帖子

我似乎找不到像以下示例中提取所有注释的方法.

>>> import re
>>> string = '''
... <!-- one 
... -->
... <!-- two -- -- -->
... <!-- three -->
... '''
>>> m = re.findall ( '<!--([^\(-->)]+)-->', string, re.MULTILINE)
>>> m
[' one \n', ' three ']

two -- --由于正则表达式错误,阻止与最不匹配.有人可以指出我正确的方向如何提取两个字符串之间的匹配.

嗨,我已经测试了你们在评论中建议的内容......这里是工作解决方案,几乎没有升级.

>>> m = re.findall ( '<!--(.*?)-->', string, re.MULTILINE)
>>> m
[' two -- -- ', ' three ']
>>> m = re.findall ( '<!--(.*\n?)-->', string, re.MULTILINE)
>>> m
[' one \n', ' two -- …

我正在寻找一种方法来创建相同类的两个或多个实例之间的子父关系形式的层次结构.

如何在嵌套字典中创建这样的对象,例如？这甚至可能吗？是否还有其他方法可以推荐这样的任务？

# -*- coding: utf-8 -*-

from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import create_engine, exists
from sqlalchemy.orm import relationship, sessionmaker
from sqlalchemy.schema import Column, ForeignKey
from sqlalchemy.types import Integer, String

Base = declarative_base()

class Person(Base):
    __tablename__ = 'person';
    id = Column(Integer, primary_key=True)
    name = Column(String, nullable=False)
    parent_id = Column(Integer, ForeignKey('person.id'))

    def __init__(self, **kwargs):
        self.parent_id = kwargs.get('parent_id', None)
        self.name = kwargs.get('name')
        self.team = kwargs.get('team', [])
        # Is it possible to create more object of this type
        # and establish that …